根据凯撒密码\Playfair密码的原理使用c++编写程序，对输入的符号串能够根据设置的密钥分别正确实现加密和解密功能。

非常感谢您的问题。根据凯撒密码和Playfair密码的原理，使用C编写程序可以对输入的符号串进行加密和解密。该程序需要设置正确的密钥，才能实现正确的加密和解密功能。如果您有特定的加密或解密算法要求，可以提供更多细节，以便我更好地回答您的问题。

相关问题

根据凯撒密码\Playfair密码的原理使用c++写代码，对输入的符号串能够根据设置的密钥分别正确实现加密和解密功能

以下是凯撒密码的实现代码，用于加密和解密一个输入字符串，使用给定的密钥：

#include <stdio.h>

void caesar_encrypt(char plaintext[], int shift);
void caesar_decrypt(char ciphertext[], int shift);

int main() {
    char message[100];
    int key;

    printf("Enter message: ");
    fgets(message, sizeof(message), stdin);

    printf("Enter key: ");
    scanf("%d", &key);

    caesar_encrypt(message, key);
    printf("Encrypted message: %s\n", message);

    caesar_decrypt(message, key);
    printf("Decrypted message: %s\n", message);

    return 0;
}

void caesar_encrypt(char plaintext[], int shift)
{
    char c;
    int i;

    for (i = 0; plaintext[i] != '\0'; i++) {
        c = plaintext[i];

        if (c >= 'a' && c <= 'z') {
            c = (c - 'a' + shift) % 26 + 'a';
        } else if (c >= 'A' && c <= 'Z') {
            c = (c - 'A' + shift) % 26 + 'A';
        }

        plaintext[i] = c;
    }
}

void caesar_decrypt(char ciphertext[], int shift)
{
    caesar_encrypt(ciphertext, 26 - shift);
}

以下是 Playfair 密码的实现代码。它使用一个 5x5 的矩阵，该矩阵由一个关键词和其他字母组成，其中 J 被忽略：

#include <stdio.h>
#include <string.h>

#define MATRIX_DIM 5
#define MATRIX_SIZE (MATRIX_DIM * MATRIX_DIM)
#define ENCRYPT 1
#define DECRYPT -1

void playfair_encrypt(char plaintext[], char key[]);
void playfair_decrypt(char ciphertext[], char key[]);

int main() {
    char message[100];
    char key[100];

    printf("Enter message: ");
    fgets(message, sizeof(message), stdin);

    printf("Enter key: ");
    fgets(key, sizeof(key), stdin);

    playfair_encrypt(message, key);
    printf("Encrypted message: %s\n", message);

    playfair_decrypt(message, key);
    printf("Decrypted message: %s\n", message);

    return 0;
}

char* remove_duplicates(char s[]) {
  int len = strlen(s);
  char *result = malloc(len + 1);
  memset(result, '\0', len+1);

  int i = 0;
  while (i < len) {
    int j = i+1;
    while (j < len) {
      if (s[j] == s[i]) {
        break;
      }
      j++;
    }
    if (j == len) {
      strncat(result, &s[i], 1);
    }
    i++;
  }

  return result;
}

void fill_matrix(char key[], char matrix[]) {
    const char* alphabet = "abcdefghiklmnopqrstuvwxyz";
    int len = strlen(key);

    // Remove duplicate letters from key
    char* no_duplicates = remove_duplicates(key);
    len = strlen(no_duplicates);

    // Fill key into matrix
    int i;
    for (i = 0; i < len; i++) {
        matrix[i] = no_duplicates[i];
    }

    // Fill remaining letters from alphabet
    int j;
    for (i = len, j = 0; j < 25 - len; j++) {
        if (strchr(matrix, alphabet[j]) == NULL) {
            matrix[i] = alphabet[j];
            i++;
        }
    }

    free(no_duplicates);
}

void print_matrix(char matrix[]) {
    int i;
    for (i = 0; i < MATRIX_SIZE; i++) {
        printf("%c ", matrix[i]);
        if ((i+1) % MATRIX_DIM == 0) {
            printf("\n");
        }
    }
}

void get_positions(char c, char matrix[], int positions[]) {
    int i;

    for (i = 0; i < MATRIX_SIZE; i++) {
        if (matrix[i] == c) {
            positions[0] = i % MATRIX_DIM;
            positions[1] = i / MATRIX_DIM;
            return;
        }
    }

    // Letter not in matrix
    positions[0] = -1;
    positions[1] = -1;
}

void playfair_transform(char plaintext[], int direction, char key[]) {
    char matrix[MATRIX_SIZE];
    fill_matrix(key, matrix);
    print_matrix(matrix);

    char c1, c2;
    int p1[2], p2[2], i;

    for (i = 0; plaintext[i] != '\0'; i++) {
        c2 = plaintext[i];

        // Ignore J
        if (c2 == 'j') {
            c2 = 'i';
        }

        if (c2 >= 'a' && c2 <= 'z') {
            if (i > 0 && c2 == c1) {
                // Special case: replace last character if it is the same
                if ((i+1) % 2 == 0) {
                    c1 = plaintext[i-1];
                } else {
                    c1 = plaintext[i+1];
                }
                c2 = 'x';
            }

            c1 = plaintext[i-1];
            if (i == 0 || c1 == 'j') {
                c1 = c2;
            }

            // Ignore J
            if (c1 == 'j') {
                c1 = 'i';
            }

            get_positions(c1, matrix, p1);
            get_positions(c2, matrix, p2);

            if (p1[0] == -1 || p2[0] == -1) {
                // Letter not in matrix
                plaintext[i] = '?';
            } else {
                if (p1[0] == p2[0]) {
                    // Same column, shift down or up
                    p1[1] = (p1[1] + direction) % MATRIX_DIM;
                    p2[1] = (p2[1] + direction) % MATRIX_DIM;
                } else if (p1[1] == p2[1]) {
                    // Same row, shift left or right
                    p1[0] = (p1[0] + direction) % MATRIX_DIM;
                    p2[0] = (p2[0] + direction) % MATRIX_DIM;
                } else {
                    // Rectangle, switch rows
                    int tmp = p1[0];
                    p1[0] = p2[0];
                    p2[0] = tmp;
                }

                plaintext[i-1] = matrix[p1[1]*MATRIX_DIM + p1[0]];
                plaintext[i] = matrix[p2[1]*MATRIX_DIM + p2[0]];
            }
        }
    }
}

void playfair_encrypt(char plaintext[], char key[]) {
    playfair_transform(plaintext, ENCRYPT, key);
}

void playfair_decrypt(char ciphertext[], char key[]) {
    playfair_transform(ciphertext, DECRYPT, key);
}

根据凯撒密码\Playfair密码的原理写代码，对输入的符号串能够根据设置的密钥分别正确实现加密和解密功能

非常感谢您的提问，我可以为您提供以下代码实现凯撒密码和Playfair密码的加密和解密功能：

凯撒密码：

def caesar_cipher(plain_text, key):
    cipher_text = ""
    for ch in plain_text:
        if ch.isalpha():
            new_ch = chr((ord(ch) - ord('a') + key) % 26 + ord('a'))
            cipher_text += new_ch
        else:
            cipher_text += ch
    return cipher_text

def caesar_decipher(cipher_text, key):
    return caesar_cipher(cipher_text, 26 - key)

Playfair密码：

def gen_playfair_table(key):
    key = key.lower().replace(" ", "")
    key_set = set(key)
    alphabet = "".join([chr(ord('a') + i) for i in range(26)])
    table_list = []
    for ch in key:
        if ch in alphabet:
            alphabet = alphabet.replace(ch, "")
            table_list.append(ch)
    for ch in alphabet:
        table_list.append(ch)
    table_str = "".join(table_list)
    table = []
    for i in range(5):
        row = table_str[i * 5 : (i + 1) * 5]
        table.append(row)
    return table

def playfair_cipher(plain_text, key):
    table = gen_playfair_table(key)
    cipher_text = ""
    plain_text = plain_text.lower().replace(" ", "")
    if len(plain_text) % 2 == 1:
        plain_text += "x"
    for i in range(0, len(plain_text), 2):
        ch1, ch2 = plain_text[i], plain_text[i + 1]
        row1, col1 = 0, 0
        row2, col2 = 0, 0
        for j in range(5):
            if ch1 in table[j]:
                row1, col1 = j, table[j].find(ch1)
            if ch2 in table[j]:
                row2, col2 = j, table[j].find(ch2)
        if row1 == row2:
            cipher_ch1 = table[row1][(col1 + 1) % 5]
            cipher_ch2 = table[row2][(col2 + 1) % 5]
        elif col1 == col2:
            cipher_ch1 = table[(row1 + 1) % 5][col1]
            cipher_ch2 = table[(row2 + 1) % 5][col2]
        else:
            cipher_ch1 = table[row1][col2]
            cipher_ch2 = table[row2][col1]
        cipher_text += cipher_ch1 + cipher_ch2
    return cipher_text

def playfair_decipher(cipher_text, key):
    table = gen_playfair_table(key)
    plain_text = ""
    cipher_text = cipher_text.lower().replace(" ", "")
    for i in range(0, len(cipher_text), 2):
        ch1, ch2 = cipher_text[i], cipher_text[i + 1]
        row1, col1 = 0, 0
        row2, col2 = 0, 0
        for j in range(5):
            if ch1 in table[j]:
                row1, col1 = j, table[j].find(ch1)
            if ch2 in table[j]:
                row2, col2 = j, table[j].find(ch2)
        if row1 == row2:
            plain_ch1 = table[row1][(col1 - 1) % 5]
            plain_ch2 = table[row2][(col2 - 1) % 5]
        elif col1 == col2:
            plain_ch1 = table[(row1 - 1) % 5][col1]
            plain_ch2 = table[(row2 - 1) % 5][col2]
        else:
            plain_ch1 = table[row1][col2]
            plain_ch2 = table[row2][col1]
        plain_text += plain_ch1 + plain_ch2
    return plain_text

请注意，这里的加密和解密函数使用了称之为“求模算术”的技巧，可以防止加密结果大于字母表中最后一个字母的 ASCII 码或小于字母表中第一个字母的 ASCII 码。同时，playfair_cipher 和 playfair_decipher 函数还处理了明文长度为奇数的情况，添加了一个"X"来填充。