C语言计算n的阶乘;计算1*3*5*7*....*(2n+1)
时间: 2023-06-01 10:04:54 浏览: 86
Sure, I can help you with that. Here's a code snippet in C language to calculate the factorial of n:
```c
#include <stdio.h>
int main() {
int n, i, factorial = 1;
printf("Enter a number: ");
scanf("%d", &n);
for (i = 1; i <= n; i++) {
factorial *= (2*i - 1);
}
printf("Factorial of %d is %d\n", n, factorial);
return 0;
}
```
This program uses a `for` loop to iterate through the odd numbers (`2n-1`) up to `2n-1`, and multiplies them together to calculate the factorial of n.
相关问题
计算n的阶乘;计算1*3*5*7*....*(2n+1)的c语言代码
好的,我来回答你的问题。
计算n的阶乘可以使用循环来实现,具体代码如下:
```c
int factorial(int n) {
int result = 1;
for (int i = 1; i <= n; i++) {
result *= i;
}
return result;
}
```
计算1*3*5*7*....*(2n+1)也可以使用循环来实现,具体代码如下:
```c
int oddProduct(int n) {
int result = 1;
for (int i = 0; i < n; i++) {
result *= (2 * i + 1);
}
return result;
}
```
编写函数,根据输入的精度值e来计算下列表达式的值。即e为1E-6时,表示某项的值小于e时停止相加π/2=1+1/3+1*2/3*5+1*2*3/3*5*7+...+1*2*3*...*n/3*5*7*...*2n+1
```c
#include <stdio.h>
double calculate_pi(double e) {
double pi = 1.0;
double item = 1.0;
int i = 1;
int j = 1;
while (item >= e) {
j += 2;
item *= i * (i + 1) / (double)(j * (j - 1));
pi += item;
i += 2;
}
return pi * 2;
}
int main() {
double e = 1e-6; double pi = calculate_pi(e);
printf("pi/2 = %lf\n", pi);
return 0;
}
```
--相关问题--:
1. 如何在C语言中计算阶乘?
2. 如何在C语言中使用