编写c语言程序，求一元二次方程ax²+bx+c=0的根

#include <stdio.h>
#include <math.h>

int main() {
float a, b, c, delta, x1, x2;

printf("请输入一元二次方程的系数：\n");
printf("a = ");
scanf("%f", &a);
printf("b = ");
scanf("%f", &b);
printf("c = ");
scanf("%f", &c);

delta = b * b - 4 * a * c;

if (delta < 0) {
printf("方程无实数解。\n");
} else if (delta == 0) {
x1 = x2 = -b / (2 * a);
printf("方程有两个相等的实数根：x1 = x2 = %.2f\n", x1);
} else {
x1 = (-b + sqrt(delta)) / (2 * a);
x2 = (-b - sqrt(delta)) / (2 * a);
printf("方程有两个不相等的实数根：x1 = %.2f，x2 = %.2f\n", x1, x2);
}

return 0;
}