Print the integers from 1 to 20 using a while loop and the int counter variable x. Print only 5 integers per line. [Hint: When x % 5 is 0, print a newline character; otherwise, print a tab character.]
时间: 2023-12-31 12:06:16 浏览: 40
Here's the code to achieve the task:
```
int x = 1;
while (x <= 20) {
cout << x << "\t";
if (x % 5 == 0) {
cout << endl; // print a newline character when x is a multiple of 5
}
x++;
}
```
Output:
```
1 2 3 4 5
6 7 8 9 10
11 12 13 14 15
16 17 18 19 20
```
相关问题
写一段完整的代码完成问题Print the integers from 1 to 20 using a while loop and the int counter variable x. Print only 5 integers per line.
当然,以下是使用C++完成该问题的完整代码:
```
#include <iostream>
using namespace std;
int main() {
int x = 1;
while (x <= 20) {
cout << x << "\t";
if (x % 5 == 0) {
cout << endl;
}
x++;
}
return 0;
}
```
代码中,我们使用了while循环,从1到20打印整数。当$x$是5的倍数时,打印一个换行符。
Write a program that reads an expression in a line as input and prints out the result. Only integers and operators below are allowed in the expression:
Sure, I can help you with that! Here is a Python code snippet that can evaluate simple arithmetic expressions containing only integers and the operators +, -, *, and /:
```python
expression = input("Enter an arithmetic expression: ")
result = eval(expression)
print("Result:", result)
```
You can copy and paste this code into a Python IDE or a Jupyter notebook and execute it. When prompted, enter an arithmetic expression like "2+3*4" and press Enter. The program will then evaluate the expression and print out the result, which in this case should be 14.
Note that the `eval()` function is used to evaluate the expression entered by the user as a Python expression. This means that the user can potentially enter any valid Python expression, so you should be careful when using this function in a production environment.