pythonCalculate A * B. 输入 Each line will contain two integers A and B. Process to end of file. Note: the length of each integer will not exceed 50000.
时间: 2023-02-12 15:12:47 浏览: 65
可以使用 Python 的内置函数 int() 将输入的字符串转换为整数,然后使用乘法运算符 * 计算 A * B。
示例代码如下:
```
while True:
try:
a, b = map(int, input().split())
print(a * b)
except:
break
```
这段代码会不断读取输入的两个整数并相乘,直到输入结束。
相关问题
style declaration must contain a value on line 3 of src/pages/Crecommendation.vue >> width: ;
这个错误是由于CSS样式表中的某个属性没有设置值导致的。在你的代码中,第三行中的`width`属性没有设置具体的值,例如`100px`或者`50%`等。你需要为该属性指定一个具体的值来解决这个错误。例如:
```
width: 100%;
```
或者
```
width: 200px;
```
Try to write an algorithm to Calculate the WPL of a Huffman Tree.
Here's the algorithm to calculate the Weighted Path Length (WPL) of a Huffman Tree:
1. Traverse the Huffman Tree in a depth-first manner.
2. At each leaf node, calculate the product of the node's weight and its depth (the number of edges from the root to the node).
3. Add up all the products calculated in step 2 to get the total WPL of the Huffman Tree.
Here's the Python implementation of the above algorithm assuming the Huffman Tree is stored as a dictionary where keys are the symbols and values are the Huffman codes:
```
def calculate_wpl(huffman_tree):
wpl = 0
stack = [(key, value, 0) for key, value in huffman_tree.items()]
while stack:
symbol, node, depth = stack.pop()
if isinstance(node, dict):
for child_symbol, child_node in node.items():
stack.append((child_symbol, child_node, depth+1))
else:
wpl += node * depth
return wpl
```
Note that the above implementation assumes that the leaf nodes of the Huffman Tree contain the symbol weights rather than the Huffman codes themselves. If the Huffman codes are stored in the leaf nodes instead, the code can be easily modified to take that into account.