用Verilog HDL设计系统,按照(3’b000->3’ b001->3’ b011->3’b111->3’b101->3b100->3’b110->3'b010->3’b000)b010->3’b000)规律工作的计数器,对输入时钟信号进行计数。要习1、系统可以异步复位,同步使能2、用四位一体数码管对计数值以二讲制形式讲行实时、同步显示并给出测试文件代码
时间: 2023-08-07 16:38:36 浏览: 179
好的,下面是带有测试文件的Verilog HDL设计:
```
module counter(
input clk, //输入时钟信号
input rst, //异步复位信号
input en, //同步使能信号
output reg [3:0] seg //四位一体数码管输出
);
reg [2:0] count; //计数器寄存器
reg [2:0] next_count; //下一个计数器值
//计数器状态转移规律
always @ (posedge clk or posedge rst) begin
if (rst) begin
count <= 3'b000; //复位时计数器清零
end else if (en) begin
count <= next_count; //使能时根据规律更新计数器值
end
end
//根据规律生成下一个计数器值
always @ (count) begin
case (count)
3'b000: next_count = 3'b001;
3'b001: next_count = 3'b011;
3'b011: next_count = 3'b111;
3'b111: next_count = 3'b101;
3'b101: next_count = 3'b100;
3'b100: next_count = 3'b110;
3'b110: next_count = 3'b010;
3'b010: next_count = 3'b000;
default: next_count = 3'b000;
endcase
end
//将计数器值转换为二进制数并输出到数码管上
always @ (count) begin
case (count)
3'b000: seg = 4'b0000;
3'b001: seg = 4'b0001;
3'b010: seg = 4'b0010;
3'b011: seg = 4'b0011;
3'b100: seg = 4'b0100;
3'b101: seg = 4'b0101;
3'b110: seg = 4'b0110;
3'b111: seg = 4'b0111;
default: seg = 4'b0000;
endcase
end
endmodule
```
测试文件代码如下:
```
`timescale 1ns / 1ps
module counter_tb;
reg clk;
reg rst;
reg en;
wire [3:0] seg;
counter uut (
.clk(clk),
.rst(rst),
.en(en),
.seg(seg)
);
initial begin
clk = 0;
rst = 1;
en = 0;
#100 rst = 0;
#100 en = 1;
end
always #5 clk = ~clk;
endmodule
```
该测试文件将时钟信号、复位信号和使能信号分别初始化为低电平、高电平和低电平,并在时钟信号上每5个时钟周期翻转一次。在100个时钟周期后,将复位信号置为低电平,再过100个时钟周期后,将使能信号置为高电平。
希望这个Verilog HDL设计和测试文件能够满足您的需求。
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