计算机博弈大赛点格棋的源代码
时间: 2023-09-13 17:10:55 浏览: 142
以下是一个使用 Monte Carlo Tree Search (MCTS) 算法的 Python 代码示例,用于在点格棋游戏中进行自动游戏。
```python
import random
class Node:
def __init__(self, state, parent=None):
self.state = state
self.parent = parent
self.children = []
self.visits = 0
self.score = 0
def add_child(self, child_state):
child = Node(child_state, parent=self)
self.children.append(child)
return child
def update(self, score):
self.visits += 1
self.score += score
def fully_expanded(self):
return len(self.children) == len(self.state.get_legal_moves())
def best_child(self, c_param=1.4):
choices_weights = [(c.score / c.visits) + c_param * math.sqrt((2 * math.log(self.visits) / c.visits)) for c in self.children]
return self.children[choices_weights.index(max(choices_weights))]
def __repr__(self):
return f"<Node: {self.state}>"
class DotsAndBoxes:
def __init__(self, size=3, players=("X", "O")):
self.size = size
self.board = [[None for _ in range(size+1)] for _ in range(size+1)]
self.players = players
self.current_player = players[0]
def get_legal_moves(self):
moves = []
for i in range(self.size+1):
for j in range(self.size+1):
if self.board[i][j] is None:
moves.append((i, j))
return moves
def get_winner(self):
x_count = 0
o_count = 0
for i in range(self.size):
for j in range(self.size):
if self.board[i][j] == self.players[0]:
x_count += 1
elif self.board[i][j] == self.players[1]:
o_count += 1
if x_count == o_count:
return None
elif x_count > o_count:
return self.players[0]
else:
return self.players[1]
def is_game_over(self):
for i in range(self.size+1):
for j in range(self.size+1):
if self.board[i][j] is None:
return False
return True
def is_valid_move(self, move):
if self.board[move[0]][move[1]] is not None:
return False
if move[0] == 0 or move[0] == self.size or move[1] == 0 or move[1] == self.size:
return True
sides = [(-1, 0), (0, -1), (1, 0), (0, 1)]
for s in sides:
if self.board[move[0]+s[0]][move[1]+s[1]] is None:
return False
return True
def apply_move(self, move):
self.board[move[0]][move[1]] = self.current_player
if self.is_box(move):
self.board[move[0]][move[1]] = self.current_player
if self.current_player == self.players[0]:
self.current_player = self.players[1]
else:
self.current_player = self.players[0]
def is_box(self, move):
sides = [(-1, 0), (0, -1), (1, 0), (0, 1)]
for s in sides:
if self.board[move[0]+s[0]][move[1]+s[1]] is None:
return False
return True
def get_score(self):
score = 0
for i in range(self.size):
for j in range(self.size):
if self.is_box((i, j)):
if self.board[i][j] == self.players[0]:
score += 1
elif self.board[i][j] == self.players[1]:
score -= 1
return score
def __repr__(self):
rows = []
for i in range(self.size+1):
row = []
for j in range(self.size+1):
if self.board[i][j] is None:
row.append(".")
else:
row.append(self.board[i][j])
rows.append(" ".join(row))
return "\n".join(rows)
class DotsAndBoxesAI:
def __init__(self, game, player, sims_per_turn=100):
self.game = game
self.player = player
self.sims_per_turn = sims_per_turn
def get_move(self):
root = Node(self.game)
for _ in range(self.sims_per_turn):
node = root
state = self.game
while node.fully_expanded() and not node.state.is_game_over():
node = node.best_child()
state.apply_move(random.choice(node.state.get_legal_moves()))
if not node.fully_expanded() and not node.state.is_game_over():
legal_moves = node.state.get_legal_moves()
move = random.choice([m for m in legal_moves if m not in [c.state for c in node.children]])
state.apply_move(move)
node = node.add_child(state)
while not state.is_game_over():
state.apply_move(random.choice(state.get_legal_moves()))
while node is not None:
node.update(state.get_score())
node = node.parent
best_move = None
best_score = float("-inf")
for child in root.children:
if child.visits > best_score:
best_move = child.state.last_move
best_score = child.score
return best_move
def __repr__(self):
return f"<DotsAndBoxesAI: {self.player}>"
```
这个代码实现了一个基于 MCTS 算法的自动点棋游戏玩家。玩家可以设置每个回合进行模拟的次数,以平衡计算时间和人类玩家的回合间隔。