用c语言给我写一个扫雷小游戏

好的，以下是一个简单的扫雷小游戏的C语言代码，你可以在终端或命令行中运行：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

#define ROWS 9
#define COLS 9
#define MINE_NUM 10

void init_board(char board[ROWS][COLS], char ch);
void display_board(char board[ROWS][COLS]);
void set_mines(char board[ROWS][COLS]);
int get_mine_count(char board[ROWS][COLS], int row, int col);
void expand_board(char board[ROWS][COLS], int row, int col);
void play_game(char board[ROWS][COLS]);

int main() {
    char board[ROWS][COLS];
    init_board(board, '*');
    set_mines(board);
    play_game(board);
    return 0;
}

void init_board(char board[ROWS][COLS], char ch) {
    int i, j;
    for (i = 0; i < ROWS; i++) {
        for (j = 0; j < COLS; j++) {
            board[i][j] = ch;
        }
    }
}

void display_board(char board[ROWS][COLS]) {
    int i, j;
    printf("  ");
    for (i = 0; i < COLS; i++) {
        printf("%d ", i);
    }
    printf("\n");
    for (i = 0; i < ROWS; i++) {
        printf("%d ", i);
        for (j = 0; j < COLS; j++) {
            printf("%c ", board[i][j]);
        }
        printf("\n");
    }
}

void set_mines(char board[ROWS][COLS]) {
    int i, j, count = 0;
    srand(time(NULL));
    while (count < MINE_NUM) {
        i = rand() % ROWS;
        j = rand() % COLS;
        if (board[i][j] != 'M') {
            board[i][j] = 'M';
            count++;
        }
    }
}

int get_mine_count(char board[ROWS][COLS], int row, int col) {
    int i, j, count = 0;
    for (i = row - 1; i <= row + 1; i++) {
        for (j = col - 1; j <= col + 1; j++) {
            if (i >= 0 && i < ROWS && j >= 0 && j < COLS && board[i][j] == 'M') {
                count++;
            }
        }
    }
    return count;
}

void expand_board(char board[ROWS][COLS], int row, int col) {
    if (row < 0 || row >= ROWS || col < 0 || col >= COLS || board[row][col] != '*') {
        return;
    }
    int count = get_mine_count(board, row, col);
    board[row][col] = count + '0';
    if (count == 0) {
        expand_board(board, row - 1, col - 1);
        expand_board(board, row - 1, col);
        expand_board(board, row - 1, col + 1);
        expand_board(board, row, col - 1);
        expand_board(board, row, col + 1);
        expand_board(board, row + 1, col - 1);
        expand_board(board, row + 1, col);
        expand_board(board, row + 1, col + 1);
    }
}

void play_game(char board[ROWS][COLS]) {
    int row, col, count = 0;
    while (1) {
        display_board(board);
        printf("Enter row and column number (separated by a space): ");
        scanf("%d %d", &row, &col);
        if (board[row][col] == 'M') {
            printf("Game over!\n");
            display_board(board);
            return;
        }
        expand_board(board, row, col);
        count++;
        if (count == ROWS * COLS - MINE_NUM) {
            printf("You win!\n");
            display_board(board);
            return;
        }
    }
}

这个程序定义了一个9x9的扫雷游戏棋盘，其中包含10个地雷。游戏开始时，所有方格都是未知的，用'*'表示。玩家可以选择一个方格进行扫描，如果方格中没有地雷，则该方格将被展开，显示相邻方格中的地雷数。如果方格中有地雷，则游戏结束。如果玩家成功地展开了所有非地雷方格，则游戏胜利。

你可以在终端或命令行中运行此程序，按照提示输入行和列号来选择扫描的方格。