传教士与野人过河五个参数伪代码
时间: 2024-09-27 08:08:23 浏览: 22
这是一个经典的计算机科学问题,通常被称为“传教士和独木舟”或“牧师与修女问题”。这个伪代码场景涉及到三个角色:传教士、修女和一头狼,以及一艘只能承载两个人的独木舟。以下是简化后的伪代码:
```text
function crossRiver(persons, boatCapacity):
# persons: [传教士, 修女, 狼]
# boatCapacity: 2 (船能载两人)
people = persons.copy()
boat = [None, None] # 初始化船为空
while len(people) > 0:
if isSafeToBoard(boat, people): # 检查船上是否安全
personToRemove = people[0] # 从岸边找两人上船
boat[0], boat[1] = personToRemove, people.pop(0)
else:
if boat[1] != wolf and boat[0] != wolf: # 如果船上无狼
boat[1] = people.pop(0) # 把一个人送回岸
else: # 否则换位置
if boat[0] == wolf:
boat[0] = personToRemove
else:
boat[1] = personToRemove
boat[0] = wolf
return boat # 返回最后船上的人员
# 判断船上是否有危险
def isSafeToBoard(boat, people):
return not (wolf in boat and (not (personOnBoat(boat[0]) or personOnBoat(boat[1]))))
# 检查船上是否有特定人物
def personOnBoat(person):
return person in boat
```