用C使用Dijkstra算法,对给定的图计算出两点间的最短路径。
时间: 2024-06-13 07:08:18 浏览: 21
以下是使用C语言实现Dijkstra算法计算两点间最短路径的示例代码:
```c
#include <stdio.h>
#include <limits.h>
#define V 9
int minDistance(int dist[], bool sptSet[]) {
int min = INT_MAX, min_index;
for (int v = 0; v < V; v++) {
if (sptSet[v] == false && dist[v] <= min) {
min = dist[v], min_index = v;
}
}
return min_index;
}
void printPath(int parent[], int j) {
if (parent[j] == -1) {
return;
}
printPath(parent, parent[j]);
printf("%d ", j);
}
void printSolution(int dist[], int n, int parent[], int src) {
printf("Vertex\t Distance\tPath");
for (int i = 0; i < V; i++) {
printf("\n%d -> %d \t\t %d\t\t%d ", src, i, dist[i], src);
printPath(parent, i);
}
}
void dijkstra(int graph[V][V], int src) {
int dist[V];
bool sptSet[V];
int parent[V];
for (int i = 0; i < V; i++) {
parent[src] = -1;
dist[i] = INT_MAX;
sptSet[i] = false;
}
dist[src] = 0;
for (int count = 0; count < V - 1; count++) {
int u = minDistance(dist, sptSet);
sptSet[u] = true;
for (int v = 0; v < V; v++) {
if (!sptSet[v] && graph[u][v] && dist[u] != INT_MAX && dist[u] + graph[u][v] < dist[v]) {
parent[v] = u;
dist[v] = dist[u] + graph[u][v];
}
}
}
printSolution(dist, V, parent, src);
}
int main() {
int graph[V][V] = {
{0, 4, 0, 0, 0, 0, 0, 8, 0},
{4, 0, 8, 0, 0, 0, 0, 11, 0},
{0, 8, 0, 7, 0, 4, 0, 0, 2},
{0, 0, 7, 0, 9, 14, 0, 0, 0},
{0, 0, 0, 9, 0, 10, 0, 0, 0},
{0, 0, 4, 14, 10, 0, 2, 0, 0},
{0, 0, 0, 0, 0, 2, 0, 1, 6},
{8, 11, 0, 0, 0, 0, 1, 0, 7},
{0, 0, 2, 0, 0, 0, 6, 7, 0}
};
dijkstra(graph, 0);
return 0;
}
```
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