matlab实现旅行商问题
时间: 2023-10-16 16:26:50 浏览: 38
旅行商问题是一个NP完全问题,因此在实际求解时需要采用一些近似算法。其中比较常用的是遗传算法和模拟退火算法。
下面给出一个基于遗传算法的Matlab代码实现:
```
function [best_path, best_dist] = tsp_ga(cities, pop_size, num_gen, elite_rate, mutation_rate)
% TSP_GA solves the Traveling Salesman Problem using a genetic algorithm
% cities: a n-by-2 matrix containing the coordinates of n cities
% pop_size: the size of the population, default is 50
% num_gen: the number of generations, default is 100
% elite_rate: the percentage of the best individuals to be kept in the next generation, default is 0.1
% mutation_rate: the probability of mutation, default is 0.01
% default parameters
if nargin < 5
mutation_rate = 0.01;
end
if nargin < 4
elite_rate = 0.1;
end
if nargin < 3
num_gen = 100;
end
if nargin < 2
pop_size = 50;
end
% number of cities
n = size(cities, 1);
% initialize population
pop = zeros(pop_size, n);
for i = 1:pop_size
pop(i,:) = randperm(n);
end
% main loop
for gen = 1:num_gen
% evaluate fitness of each individual
dist = zeros(pop_size, 1);
for i = 1:pop_size
path = pop(i,:);
dist(i) = 0;
for j = 1:n-1
dist(i) = dist(i) + norm(cities(path(j+1),:) - cities(path(j),:));
end
dist(i) = dist(i) + norm(cities(path(1),:) - cities(path(n),:)); % add distance from last to first city
end
[sorted_dist, idx] = sort(dist);
best_path = pop(idx(1),:);
best_dist = sorted_dist(1);
% selection
elite_size = round(elite_rate * pop_size);
elite_pop = pop(idx(1:elite_size),:);
nonelite_size = pop_size - elite_size;
nonelite_pop = zeros(nonelite_size, n);
for i = 1:nonelite_size
% tournament selection
k = randi(pop_size, 1, 2);
if dist(k(1)) < dist(k(2))
nonelite_pop(i,:) = pop(k(1),:);
else
nonelite_pop(i,:) = pop(k(2),:);
end
end
pop = [elite_pop; nonelite_pop];
% crossover
for i = 1:2:nonelite_size
% choose two parents
p = randperm(nonelite_size, 2);
parent1 = nonelite_pop(p(1),:);
parent2 = nonelite_pop(p(2),:);
child = zeros(1, n);
% choose a random segment from parent1
seg_start = randi(n);
seg_end = randi([seg_start+1,n]);
child(seg_start:seg_end) = parent1(seg_start:seg_end);
% insert remaining cities from parent2
idx = 1;
for j = 1:n
if child(j) == 0
while ismember(parent2(idx), child)
idx = idx + 1;
if idx > n
idx = 1;
end
end
child(j) = parent2(idx);
idx = idx + 1;
if idx > n
idx = 1;
end
end
end
pop(elite_size+i,:) = child;
end
% mutation
for i = 1:pop_size
if rand < mutation_rate
% swap two random cities
j = randi(n, 1, 2);
pop(i,[j(1),j(2)]) = pop(i,[j(2),j(1)]);
end
end
end
end
```
使用方法:
首先定义一组城市坐标,例如:
```
cities = [0, 0;
1, 1;
2, 1;
1, 2;
2, 2];
```
然后调用`tsp_ga`函数求解:
```
[best_path, best_dist] = tsp_ga(cities);
```
其中`best_path`为最优路径,`best_dist`为最优路径长度。
需要注意的是,由于遗传算法是一种随机算法,因此每次运行的结果可能会有所不同。