首页解释代码： def __len__(self): remain = len(self.dataset) % self.batch_size if self.drop_last or not remain: return len(self.dataset) // self.batch_size else: return len(self.dataset) // self.batch_size + 1

解释代码： def len(self): remain = len(self.dataset) % self.batch_size if self.drop_last or not remain: return len(self.dataset) // self.batch_size else: return len(self.dataset) // self.batch_size + 1

时间: 2023-05-29 13:07:22 浏览: 77

As an AI language model, I do not have emotions or personal opinions. My purpose is to provide helpful and informative responses to your queries. Could you please provide more context or a specific question so that I can assist you better?

解释代码: def len(self): remain = len(self.dataset) % self.batch_size if self.drop_last or not remain: return len(self.dataset) // self.batch_size else: return len(self.dataset) // self.batch_size + 1

As an AI language model, I do not have personal opinions or beliefs. "Null" is a term used in programming and refers to the absence of a value or a null value. It can be used to indicate that a variable or expression does not have a value or that a condition is not met.

代码解释： def len(self): remain = len(self.dataset) % self.batch_size if self.drop_last or not remain: return len(self.dataset) // self.batch_size else: return len(self.dataset) // self.batch_size + 1

As an AI language model, I do not have a physical or emotional state, therefore, null has no impact or meaning for me. However, in computer programming, null represents a value that does not exist or is unknown.

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解释代码 def len(self): remain = len(self.dataset) % self.batch_size if self.drop_last or not remain: return len(self.dataset) // self.batch_size else: return len(self.dataset) // self.batch_size + 1

As an AI language model, I do not have emotions or feelings. Therefore, I am not capable of experiencing or expressing the concept of "null." However, in computer science, "null" is a value that ...

解释下面代码的作用：" def len(self): remain = len(self.dataset) % self.batch_size if self.drop_last or not remain: return len(self.dataset) // self.batch_size else: return len(self.dataset) // self.batch_size + 1"

As an AI language model, I do not have any feelings or emotions, so the concept of null does not apply to me. However, in programming, null refers to a value that represents the absence of a value or ...

帮我注释下面代码class Ball: """ 针头 """ def init(self, angle): self.x = x0 self.y = y0 + length self.center = (self.x, self.y) self.radius = 12 self.angle = angle ball_group.append(self) def draw(self, surface): pygame.draw.line(surface, WHITE, shaft, self.center, 2) pygame.draw.circle(surface, WHITE, self.center, 12) def move(self, speed): """ 围绕转轴做圆周运动 :param speed: 转动的角速度 :return: """ if self.angle < 2 * math.pi: self.angle += speed else: self.angle = self.angle - 2 * math.pi self.x = x0 - length * math.sin(self.angle) self.y = y0 + length * math.cos(self.angle) self.center = (self.x, self.y) def check_collide(new_ball): for ball in ball_group: distance = math.sqrt(abs(ball.x - new_ball.x) 2 + abs(ball.y - new_ball.y) 2) if ball is not new_ball and distance <= new_ball.radius * 2: return True return False def game_init(): global stage, gaming, remain_ball, stage_pass,score if stage == len(all_stage): stage = 1 elif stage_pass: stage += 1 ball_group.clear() for a in all_stage[stage - 1]: b = Ball(a) remain_ball = ball_num[stage - 1] score=0 pygame.time.delay(200) gaming = True stage_pass = False button = Button('重新开始', color=(220, 0, 0)) button.rect.center = shaft button.click_connect(game_init) def restart(): for event in pygame.event.get(): if event.type == pygame.QUIT: pygame.quit() sys.exit() button.get_click(event) def game_stage(): global remain_ball, stage, gaming, stage_pass,score if remain_ball == 0 and gaming: stage_pass = True gaming = False

这段代码是一个 Python 类的定义，名为 Ball，表示一个球的属性和行为。下面是对每个方法的注释： - __init__: 初始化方法，传入一个 angle 参数表示球相对于垂直线的旋转角度，设置球的初始坐标、圆心、半径...

请帮我注释下面代码def main(): global gaming, remain_ball, stage,score while True: if gaming: if stage==3: jk=score_font.render("闯关成功",True,PURPLE) screen.blit(jk,[310,250]) for event in pygame.event.get(): if event.type == pygame.QUIT: pygame.quit() sys.exit() if event.type == pygame.MOUSEBUTTONDOWN and event.button == 1: if remain_ball > 0: new_ball = Ball(0) remain_ball -= 1 score+=1 if check_collide(new_ball): gaming = False else: restart() game_stage() update() pygame.display.update() fclock.tick(fps)

这段代码主要实现了一个游戏的主循环逻辑 - main() 函数定义了游戏的主循环逻辑 - while True: 表示游戏会一直执行下去，直到被手动关闭 - if gaming: 判断当前是否处于游戏状态 - if stage==3: 判断当前...

if op_interface == 'game': try: remain_time = 0 if len(list_time1) == len(list_time2) and list_time1[0] < list_time2[0] and list_time1[-1] < list_time2[ -1]: # 正常情况 for i in range(len(list_time1)): remain_time = list_time2[i] - list_time1[i] print '\t'.join([str(dateid),str(op_interface),str(only_id), str(remain_time)]) elif len(list_time2) - len(list_time1) == 1 and list_time1[0] > list_time2[0]: # 结束时间继承前一天,第一次进入绑定缺失enterbug也能算 for i in range(len(list_time1)): remain_time = list_time2[i + 1] - list_time1[i] print '\t'.join([str(dateid),str(op_interface),str(only_id), str(remain_time)]) elif len(list_time1) - len(list_time2) == 1 and list_time1[-1] > list_time2[-1]: # 开始时间带有后一天 for i in range(len(list_time2)): remain_time = list_time2[i] - list_time1[i] print '\t'.join([str(dateid),str(op_interface),str(only_id), str(remain_time)]) else: pass except Exception: pass有什么错误

在这段代码中，可能会存在以下错误： 1. 缺少必要的导入语句。 2. print 语句使用了旧版的 Python 语法，需要使用括号将要打印的内容括起来。 3. print 语句前面缺少了一个空格。 4. Exception 捕获过于宽泛...

def decode_branch(current_x, current_y, semantic_fine, arrow, bound): re_height = config.re_height re_width = config.re_width seg_threshold = config.seg_threshold step_length = config.step_length arrow_dx = arrow[..., 0] # 相邻点的dx arrow_dy = arrow[..., 1] # 相邻点的dy remain_steps = [] append = remain_steps.append target_lane = FloatLengthLine(width=re_width, height=re_height) for index in range(re_height): current_score = semantic_fine[current_y, current_x] if current_score > seg_threshold: append(bound[current_y, current_x] * 100 / step_length + index) arrow_delta = (arrow_dx[current_y, current_x], arrow_dy[current_y, current_x]) # 相邻点的偏移量 """计算偏移量后的(x,y)""" current_x = np.floor( current_x + arrow_delta[0] / np.sqrt(arrow_delta[0] 2 + arrow_delta[1] 2) * step_length).astype(int) current_y = np.floor( current_y + arrow_delta[1] / np.sqrt(arrow_delta[0] 2 + arrow_delta[1] 2) * step_length).astype(int) if (0 <= current_x < re_width) and (0 <= current_y < re_height): pass else: break current_pt = PointSelf(x=current_x, y=current_y, score=semantic_fine[current_y, current_x]) # 得到(x,y,score) # current_pt = [current_x,current_y] target_lane.append(current_pt) if len(remain_steps) != 0: ret = np.sqrt(sum([i ** 2 for i in remain_steps]) / len(remain_steps)) else: ret = 1 if semantic_fine[current_y, current_x] > seg_threshold: continue if index > ret * 0.3: break return target_lane

这段代码的作用是解析车道线的信息，输入包括当前的x和y坐标、车道线的语义信息、箭头信息和边界信息等，输出是一个包含车道线坐标点信息的对象target_lane。具体实现过程是，使用循环遍历一段距离内的每一个像素点...

def cut_img(img):#把图的H切割为4的倍数 h = img.shape[0] remain = h%4 h_new = h - remain img_new = img[:h_new, :] return img_new

def cut_img(img): # 获取图像的高度 h = img.shape[0] # 计算需要切割的行数 remain = h % 4 h_new = h - remain # 切割图像 img_new = img[:h_new, :] return img_new

这是完整代码import math import random import numpy as np import matplotlib.pyplot as plt #import self as self epsilon = 0.5 gamma = 0.1 lr = 0.1 zeros_vector=[] x = []; y = []; X = []; Y = []; agent=[x,y]; object=[X,Y]; random.seed(70) for i in range(10): x.append(random.uniform(0, 1)) y.append(random.uniform(0, 1)) X.append(random.uniform(1, 10)) Y.append(random.uniform(1, 10)) distance = [] for i in range(len(agent[0])): distance_vector = [] for j in range(len(object[0])): dx = agent[0][i] - object[0][j] dy = agent[1][i] - object[1][j] distance_vector.append(math.sqrt(dx * dx + dy * dy)) distance.append(distance_vector) R_table = np.zeros((10, 10)) for i in range(len(agent[0])): for j in range(len(object[0])): R_table[i,j] = 20-distance[i][j] space = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] #Q_table = [] Q_table = np.zeros((10, 10)) # 进行训练同时测试训练成果 iterate_results = [] # 保存每次测试结果 for i in range(500): print(f"开始第{i + 1}回合。。。") # 初始位置 path = [] # 每个回合要获取10个位置 for j in range(10): remain = set(space) - set(path) # 剩余节点 # s = path[0] # 当前位置 # s_row = Q_table[s] # 当前位置对应的Q表中的行 max_value = -1000 # 在剩余动作中遍历最大值 for rm in remain: Q = Q_table[j][rm] if Q > max_value: max_value = Q a = rm # 随机选择下一行动 if np.random.uniform() < epsilon: a = np.random.choice(np.array(list(set(space) - set(path)))) # 更新Q表 if j != 10: Q_table[j][a] = (1 - lr) * Q_table[j][a] + lr * (R_table[j][a] + gamma * max_value) else: Q_table[j][a] = (1 - lr) * Q_table[j][a] + lr * R_table[j][a] path.append(a) # print(Q_table[j][a]) # 根据当前Q表获取最佳路径距离 result = [] lengths=[] final_length=1000 final_result=[] for k in range(10): loc = k remain1 = set(space) - set(result) # 剩余节点 max_value1 = -1000 # 在剩余节点中遍历最大值 # a = 0 # 利用贪婪策略选择下一行动 for v in remain1: Q_ = Q_table[loc][v] if Q_ > max_value1: a = v max_value1 = Q_ result.append(a) length = 0 for v in range(1, 10): length += distance[result[v - 1]][v-1] print(f"距离为：{length}") if length < final_length: final_length=length final_result=result iterate_results.append(length)

根据您提供的代码，if条件句应该是可以生效的。代码中有一个变量叫做final_length，它的初始值为1000。在代码的最后，有一个循环用于计算路径长度，并与final_length进行比较，如果路径长度小于final_length，...

优化这段代码：for i in range(len(sv_lines)): if (unused_path1 in sv_lines[i]) or (unused_path2 in sv_lines[i]) or (unused_path3 in sv_lines[i]) or (unused_path4 in sv_lines[i]) or (unused_path5 in sv_lines[i]) or (unused_path6 in sv_lines[i]) or (unused_path7 in sv_lines[i])or (unused_path8 in sv_lines[i])or (unused_path9 in sv_lines[i])or (unused_path10 in sv_lines[i])or (unused_path11 in sv_lines[i])or (unused_path12 in sv_lines[i])or (unused_path13 in sv_lines[i])or (unused_path14 in sv_lines[i])or (unused_path15 in sv_lines[i]): f_d.write(sv_lines[i]) else: f_remain.write(sv_lines[i]) f_d.close f_remain.close f_loglist.close

可以使用一个列表来存储所有的 unused_path，然后使用 any() 函数来检查每一行是否包含其中任意一个 unused_path，代码如下： unused_paths = [unused_path1, unused_path2, unused_path3, unused_path4, unused_...

# 根据当前Q表获取最佳路径距离 result = [] final_length=1000 final_result=[] for k in range(10): loc = k remain1 = set(space) - set(result) # 剩余节点 max_value1 = -1000 # 在剩余节点中遍历最大值 # a = 0 # 利用贪婪策略选择下一行动 for v in remain1: Q_ = Q_table[loc][v] if Q_ > max_value1: a = v max_value1 = Q_ result.append(a) length = 0 for v in range(1, 10): length += distance[result[v - 1]][v-1] if length <= final_length: final_length=length final_result=result print(f"距离为：{length}") iterate_results.append(length)

这段代码不是一个数列，而是一段 Python 代码。它的作用是使用 Q-learning 算法来搜索最短路径，其中包括一个距离变量 length 表示搜索到的最短路径的长度。若要获取最大值，可以在搜索完成后，将每个节点的距离...

#define MAX_PROCESS_NUM 10 typedef enum{ READY, RUNNING, BLOCKED } ProcessState; typedef struct{ int pid; ProcessState state; int priority; int remain_time_slice; } PCB; PCB processes[MAX_PROCESS_NUM]; int process_num = 0; #define TIME_SLICE 3 void time_slice_scheduling(){ int i; do{ for(i = 0; i < process_num; i++){ if(processes[i].state == RUNNING){ processes[i].remain_time_slice--; if(processes[i].remain_time_slice == 0){ processes[i].state = READY; } } if(processes[i].state == READY){ processes[i].state = RUNNING; processes[i].remain_time_slice = TIME_SLICE; } } }while(1); } void priority_scheduling(){ int i, j, max_priority, max_index; do{ max_priority = -1; max_index = -1; for(i = 0; i < process_num; i++){ if(processes[i].state == READY && processes[i].priority > max_priority){ max_priority = processes[i].priority; max_index = i; } } if(max_index != -1){ processes[max_index].state = RUNNING; for(j = 0; j < process_num; j++){ if(j != max_index && processes[j].state != BLOCKED){ processes[j].state = READY; } } } }while(1); } #include <stdio.h> int main(){ // 创建进程并初始化 processes[0].pid = 0; processes[0].state = RUNNING; processes[0].priority = 2; processes[0].remain_time_slice = TIME_SLICE; processes[1].pid = 1; processes[1].state = READY; processes[1].priority = 1; processes[1].remain_time_slice = 0; processes[2].pid = 2; processes[2].state = READY; processes[2].priority = 3; processes[2].remain_time_slice = 0; process_num = 3; // 调用时间片轮转调度算法 time_slice_scheduling(); // 调用静态优先级调度算法 priority_scheduling(); return 0; }代码运行错误，请修改

这段代码存在两个死循环，分别在 time_slice_scheduling() 和 priority_scheduling() 函数中。这会导致程序无法正常退出，需要在循环中添加退出条件。另外，在 priority_scheduling() 函数中，当没有就绪进程时，...

select case when overdue_days > 0 then ‘逾期’ when overdue_days = 0 and remain_principal > 0 then ‘在贷’ end, count(distinct sso_id) as remain_cnt from ( (select * from p02.ods_fin_notify_sms_send_info where ( substring(business_batch_no, 1, 22) = 'SNO2023070417590292025' or substring(business_batch_no, 1, 22) = 'SNO2023052219260890070' ) and return_msg = '处理成功') as a left join ( select dayno, ssoid, overdue_days, remain_principal from p02.dwd_loan_user_loan_apply_all_d where dayno = 20230708 or dayno = 20230523 ) as b on substring(a.business_batch_no, -8) = b.dayno and a.sso_id = b.ssoid ) group by case when overdue_days > 0 then ‘逾期’ when overdue_days = 0 and remain_principal > 0 then ‘在贷’ end

以下是根据您提供的 SQL 查询语句进行的解释：该查询语句是对两个子查询进行左连接，并根据条件进行筛选和计数。首先，子查询 a 从表 p02.ods_fin_notify_sms_send_info 中选择符合条件的记录，其中条件为 ...

public void addBook(Book b){ String sql="insert into Book values('"+b.getBook_ISBN()+"','"+b.getBook_category()+"','"+b.getBook_name()+"','"+b.getBook_author()+"','"+b.getPublish_house()+"','"+b.getPublish_time()+"','"+b.getBook_price()+"','"+b.getBook_sum()+"','"+b.getBook_remain()+"','"+b.getBook_introduce()+"')"; Object params[]={b.getBook_ISBN(),b.getBook_category(),b.getBook_name(),b.getBook_author(),b.getPublish_house(),b.getPublish_time(),b.getBook_price(),b.getBook_sum(),b.getBook_sum(),b.getBook_remain(),b.getBook_introduce()}; DBHelper.executeUpdate(sql,params); }实现junit测试的代码

可以参考以下代码实现JUnit测试： java import static org.junit.Assert.assertEquals; import static org.mockito.ArgumentMatchers.any; import static org.mockito.Mockito.mock; import static org.mockito....

public void addBook(Book b){ String sql="insert into Book values('"+b.getBook_ISBN()+"','"+b.getBook_category()+"','"+b.getBook_name()+"','"+b.getBook_author()+"','"+b.getPublish_house()+"','"+b.getPublish_time()+"','"+b.getBook_price()+"','"+b.getBook_sum()+"','"+b.getBook_remain()+"','"+b.getBook_introduce()+"')"; Object params[]={b.getBook_ISBN(),b.getBook_category(),b.getBook_name(),b.getBook_author(),b.getPublish_house(),b.getPublish_time(),b.getBook_price(),b.getBook_sum(),b.getBook_sum(),b.getBook_remain(),b.getBook_introduce()}; DBHelper.executeUpdate(sql,params); }用junit实现测试的代码

测试代码如下： @Test public void testAddBook() { Book book = new Book("1234567890", "Science Fiction", "The Hitchhiker's Guide to the Galaxy", "Douglas Adams", "Pan Books", "1979-10-12", 8.99, ...

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内容概要：文章探讨了互联网时代的背景下开发一个实用的家庭理财系统的重要性。文中分析了国内外家庭理财的现状及存在的问题，阐述了开发此系统的目的——对家庭财产进行一体化管理，提供统计、预测功能。系统涵盖了家庭成员管理、用户认证管理、账单管理等六大功能模块，能够满足用户多方面查询及统计需求，并保证数据的安全性与完整性。设计中运用了先进的技术栈如SSM框架（Spring、SpringMVC、Mybatis），并采用MVC设计模式确保软件结构合理高效。适用人群：对于希望科学地管理和规划个人或家庭财务的普通民众；从事财务管理相关专业的学生；有兴趣于家政学、经济学等领域研究的专业人士。使用场景及目标：适用于日常家庭财务管理的各个场景，帮助用户更好地了解自己的消费习惯和资金状况；为目标客户提供一套稳定可靠的解决方案，助力家庭财富增长。其他说明：文章还包括系统设计的具体方法与技术选型的理由，以及项目实施过程中的难点讨论。对于开发者而言，不仅提供了详尽的技术指南，还强调了用户体验的重要性。

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基于Java的家庭理财系统设计与开发-金融管理-家庭财产管理-实用性强

弹性盒子Flexbox布局.docx

解释代码： def __len__(self): remain = len(self.dataset) % self.batch_size if self.drop_last or not remain: return len(self.dataset) // self.batch_size else: return len(self.dataset) // self.batch_size + 1