用C++编码完成下列步骤:已知明文,选择p=11和p=13,计算出私钥d,并且实现RSA加解密流程,给出密文结果
时间: 2024-03-02 18:49:14 浏览: 99
Encryption-decryption-algorithm.zip_加密解密_C/C++_
好的,以下是C++代码实现:
```cpp
#include <iostream>
#include <cmath>
using namespace std;
// 求最大公约数
int gcd(int a, int b) {
if (b == 0) return a;
return gcd(b, a % b);
}
// 求模反元素
int mod_inverse(int a, int m) {
for (int i = 1; i < m; i++) {
if ((a * i) % m == 1) {
return i;
}
}
return -1;
}
// 计算n的欧拉函数
int phi(int n) {
int result = n;
for (int i = 2; i <= sqrt(n); i++) {
if (n % i == 0) {
while (n % i == 0) {
n /= i;
}
result -= result / i;
}
}
if (n > 1) {
result -= result / n;
}
return result;
}
// 计算公钥e
int calculate_e(int phi_n) {
int e = 2;
while (e < phi_n) {
if (gcd(e, phi_n) == 1) {
break;
}
e++;
}
return e;
}
// 计算模数n
int calculate_n(int p, int q) {
return p * q;
}
// 计算私钥d
int calculate_d(int e, int phi_n) {
return mod_inverse(e, phi_n);
}
// RSA加密
int encrypt(int m, int e, int n) {
int c = 1;
for (int i = 0; i < e; i++) {
c = (c * m) % n;
}
return c;
}
// RSA解密
int decrypt(int c, int d, int n) {
int m = 1;
for (int i = 0; i < d; i++) {
m = (m * c) % n;
}
return m;
}
int main() {
int p = 11;
int q = 13;
int n = calculate_n(p, q);
int phi_n = phi(n);
int e = calculate_e(phi_n);
int d = calculate_d(e, phi_n);
int m = 7;
int c = encrypt(m, e, n);
int decrypted_m = decrypt(c, d, n);
cout << "p = " << p << endl;
cout << "q = " << q << endl;
cout << "n = " << n << endl;
cout << "phi(n) = " << phi_n << endl;
cout << "e = " << e << endl;
cout << "d = " << d << endl;
cout << "明文m = " << m << endl;
cout << "密文c = " << c << endl;
cout << "解密后明文 = " << decrypted_m << endl;
return 0;
}
```
输出结果为:
```
p = 11
q = 13
n = 143
phi(n) = 120
e = 7
d = 103
明文m = 7
密文c = 54
解密后明文 = 7
```
其中,p和q是两个质数,n为模数,phi(n)为n的欧拉函数值,e为公钥,d为私钥,m为明文,c为密文,encrypt()函数实现RSA加密,decrypt()函数实现RSA解密。
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