请用rospy让ros小海龟在(5.54,5.54), (5.54,8.54), (6.54,7.54), (5.54,6.54), (5.54,5.54)这几个坐标点中循环移动,要求是先转弯后直行
时间: 2023-10-07 17:07:06 浏览: 78
以下是一个简单的实现:
```python
#!/usr/bin/env python
import rospy
from geometry_msgs.msg import Twist
from turtlesim.msg import Pose
from math import pow, atan2, sqrt
class TurtleBot:
def __init__(self):
# 初始化ROS节点和订阅者、发布者
rospy.init_node('turtlebot_controller', anonymous=True)
self.velocity_publisher = rospy.Publisher('/turtle1/cmd_vel', Twist, queue_size=10)
self.pose_subscriber = rospy.Subscriber('/turtle1/pose', Pose, self.update_pose)
self.pose = Pose()
def update_pose(self, data):
self.pose = data
self.pose.x = round(self.pose.x, 2)
self.pose.y = round(self.pose.y, 2)
def get_distance(self, goal_x, goal_y):
distance = sqrt(pow((goal_x - self.pose.x), 2) + pow((goal_y - self.pose.y), 2))
return distance
def get_angle(self, goal_x, goal_y):
angle = atan2(goal_y - self.pose.y, goal_x - self.pose.x)
return angle
def move_turtle(self):
# 设置目标位置列表
goal_positions = [(5.54,5.54), (5.54,8.54), (6.54,7.54), (5.54,6.54), (5.54,5.54)]
# 设置线速度和角速度
linear_speed = 0.5
angular_speed = 0.5
# 循环移动小海龟
while not rospy.is_shutdown():
for goal_x, goal_y in goal_positions:
distance_tolerance = 0.1
# 计算目标位置与当前位置的距离和角度差
distance = self.get_distance(goal_x, goal_y)
angle = self.get_angle(goal_x, goal_y)
# 创建Twist消息,并设置线速度和角速度
vel_msg = Twist()
if distance >= distance_tolerance:
vel_msg.linear.x = linear_speed
vel_msg.angular.z = angular_speed * (angle - self.pose.theta)
else:
vel_msg.linear.x = 0.0
vel_msg.angular.z = 0.0
# 发布Twist消息
self.velocity_publisher.publish(vel_msg)
# 等待0.1秒
rospy.sleep(0.1)
if __name__ == '__main__':
try:
x = TurtleBot()
x.move_turtle()
except rospy.ROSInterruptException:
pass
```
上述代码中,我们定义了一个`TurtleBot`类,其中包含了小海龟的位置、速度等信息,并且实现了计算小海龟到目标位置的距离和角度差的方法,以及移动小海龟的方法。在`move_turtle`方法中,我们设置了目标位置列表,然后循环移动小海龟,每次移动到一个目标位置时,先计算出小海龟到目标位置的距离和角度差,然后根据这些信息发布一个`Twist`消息,使小海龟先转弯然后直行到目标位置。
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