使用c语言制作可局域网对战的五子棋代码

好的，以下是一个简单的可在局域网内对战的五子棋代码，使用C语言编写：

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <winsock2.h>

#define BUF_SIZE 100
#define BOARD_SIZE 15
#define EMPTY 0
#define BLACK 1
#define WHITE 2

// 棋盘和玩家信息
int board[BOARD_SIZE][BOARD_SIZE];
char player1[BUF_SIZE] = "Player1";
char player2[BUF_SIZE] = "Player2";

// 初始化棋盘
void init_board() {
    memset(board, EMPTY, sizeof(board));
}

// 打印棋盘
void print_board() {
    int i, j;
    printf("\n");
    for(i = 0; i < BOARD_SIZE; i++) {
        for(j = 0; j < BOARD_SIZE; j++) {
            switch(board[i][j]) {
                case EMPTY:
                    printf("+ ");
                    break;
                case BLACK:
                    printf("X ");
                    break;
                case WHITE:
                    printf("O ");
                    break;
            }
        }
        printf("\n");
    }
}

// 判断胜负
int check_win(int color) {
    int i, j, k, count;
    // 横向检查
    for(i = 0; i < BOARD_SIZE; i++) {
        for(j = 0; j < BOARD_SIZE - 4; j++) {
            count = 0;
            for(k = 0; k < 5; k++) {
                if(board[i][j+k] == color) {
                    count++;
                }
            }
            if(count == 5) {
                return 1;
            }
        }
    }
    // 纵向检查
    for(i = 0; i < BOARD_SIZE - 4; i++) {
        for(j = 0; j < BOARD_SIZE; j++) {
            count = 0;
            for(k = 0; k < 5; k++) {
                if(board[i+k][j] == color) {
                    count++;
                }
            }
            if(count == 5) {
                return 1;
            }
        }
    }
    // 左上到右下检查
    for(i = 0; i < BOARD_SIZE - 4; i++) {
        for(j = 0; j < BOARD_SIZE - 4; j++) {
            count = 0;
            for(k = 0; k < 5; k++) {
                if(board[i+k][j+k] == color) {
                    count++;
                }
            }
            if(count == 5) {
                return 1;
            }
        }
    }
    // 右上到左下检查
    for(i = 4; i < BOARD_SIZE; i++) {
        for(j = 0; j < BOARD_SIZE - 4; j++) {
            count = 0;
            for(k = 0; k < 5; k++) {
                if(board[i-k][j+k] == color) {
                    count++;
                }
            }
            if(count == 5) {
                return 1;
            }
        }
    }
    return 0;
}

// 玩家下棋
void play(int color) {
    int x, y;
    printf("\n%s's turn, please input coordinate(x,y):\n", color == BLACK ? player1 : player2);
    scanf("%d%d", &x, &y);
    while