function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1); newPop(i,:) = [pop(i1,1:c), pop(i2,c+1:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c+1:end)]; end end end有错误吗
时间: 2023-06-14 20:02:58 浏览: 58
是的,这段代码存在错误。
在第8行,应该是`newPop(i+1,:)`而不是`newPop(i 1,:)`。
此外,在第6行,应该是`c = randi(size(pop,2)-1)+1;`,因为`randi`得到的是从1到size(pop,2)-1的随机整数,而我们需要将交叉点设为从1到size(pop,2)的随机整数,所以需要加1。
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function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1); newPop(i,:) = [pop(i1,1:c), pop(i2,c+1:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c+1:end)]; end end end function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1)+1; newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c:end)]; end end end有错误吗
是的,代码中有一个错误。在第10行和第12行中,变量c的赋值语句应该为:
```c = randi(size(pop,2)-1) + 1;```
这是因为我们需要将c设为一个介于1和size(pop,2)-1之间的随机整数,而randi函数返回的是介于1和size(pop,2)-1之间的随机整数,因此我们需要将其加1才能得到正确的结果。
pop为100×36的矩阵,npop数值是100;function newPop = crossover(pop, nPop, pCross) newPop = pop; for i = 1:2:nPop if rand < pCross i1 = randi(nPop); i2 = randi(nPop); c = randi(size(pop,2)-1)+1; newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)]; newPop(i+1,:) = [pop(i2,1:c), pop(i1,c:end)]; end end end这个代码哪里错了,怎么修改
这个代码有几个错误:
1. 在定义变量 `c` 时,`1` 应该是 `+`,表示将 c 后面的部分连接在 i1 的前面,即 `c+1`。
2. 在交叉时,应该是 `i+1` 而非 `i 1`,即将第二个子代索引改为 `i+1`。
下面是修改后的代码:
```
function newPop = crossover(pop, nPop, pCross)
newPop = pop;
for i = 1:2:nPop
if rand < pCross
i1 = randi(nPop);
i2 = randi(nPop);
c = randi(size(pop,2)-1) + 1;
newPop(i,:) = [pop(i1,1:c), pop(i2,c:end)];
newPop(i+1,:) = [pop(i2,1:c), pop(i1,c:end)];
end
end
end
```
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