有函数f(x,y,z)=x+y2-z，其中x∈[2000,3000]，y∈[1,9]，z∈[10,30]的。请写出该函数采用13个用例的边界值分析法、健壮性分析法、最坏情况测试分析法设计的测试用例。并编写程序

边界值分析法：

1. x = 2000, y = 1, z = 10
2. x = 2000, y = 1, z = 30
3. x = 2000, y = 9, z = 10
4. x = 2000, y = 9, z = 30
5. x = 3000, y = 1, z = 10
6. x = 3000, y = 1, z = 30
7. x = 3000, y = 9, z = 10
8. x = 3000, y = 9, z = 30
9. x = 2500, y = 1, z = 10
10. x = 2500, y = 1, z = 30
11. x = 2500, y = 9, z = 10
12. x = 2500, y = 9, z = 30
13. x = 2500, y = 5, z = 20

健壮性分析法：

1. x = 1999, y = 0, z = 9
2. x = 3001, y = 10, z = 31
3. x = 2500, y = 10, z = 20
4. x = 2500, y = 0, z = 20

最坏情况测试分析法：

1. x = 2000, y = 1, z = 30
2. x = 2000, y = 9, z = 10
3. x = 3000, y = 1, z = 30
4. x = 3000, y = 9, z = 10
5. x = 2500, y = 1, z = 30
6. x = 2500, y = 9, z = 10
7. x = 2000, y = 5, z = 20
8. x = 3000, y = 5, z = 20
9. x = 2500, y = 1, z = 20
10. x = 2500, y = 9, z = 20

下面是 Python 代码实现，可以复制到 Python 环境中直接运行：

def f(x, y, z):
    return x + y ** 2 - z

# 边界值分析法
test_cases = [
    [2000, 1, 10],
    [2000, 1, 30],
    [2000, 9, 10],
    [2000, 9, 30],
    [3000, 1, 10],
    [3000, 1, 30],
    [3000, 9, 10],
    [3000, 9, 30],
    [2500, 1, 10],
    [2500, 1, 30],
    [2500, 9, 10],
    [2500, 9, 30],
    [2500, 5, 20]
]

print("边界值分析法测试结果：")
for i, tc in enumerate(test_cases):
    x, y, z = tc
    result = f(x, y, z)
    print(f"测试用例{i+1}: x={x}, y={y}, z={z}, result={result}")

# 健壮性分析法
test_cases = [
    [1999, 0, 9],
    [3001, 10, 31],
    [2500, 10, 20],
    [2500, 0, 20]
]

print("健壮性分析法测试结果：")
for i, tc in enumerate(test_cases):
    x, y, z = tc
    result = f(x, y, z)
    print(f"测试用例{i+1}: x={x}, y={y}, z={z}, result={result}")

# 最坏情况测试分析法
test_cases = [
    [2000, 1, 30],
    [2000, 9, 10],
    [3000, 1, 30],
    [3000, 9, 10],
    [2500, 1, 30],
    [2500, 9, 10],
    [2000, 5, 20],
    [3000, 5, 20],
    [2500, 1, 20],
    [2500, 9, 20]
]

print("最坏情况测试分析法测试结果：")
for i, tc in enumerate(test_cases):
    x, y, z = tc
    result = f(x, y, z)
    print(f"测试用例{i+1}: x={x}, y={y}, z={z}, result={result}")