求1!+3!+5!+...+11!的值。if函数求解

好的，我们可以使用 if 语句来计算阶乘并求和。下面是代码：

sum = 0
for i in range(1, 12, 2):
    factorial = 1
    if i == 1:
        factorial = 1
    elif i == 3:
        factorial = 1 * 3
    elif i == 5:
        factorial = 1 * 3 * 5
    elif i == 7:
        factorial = 1 * 3 * 5 * 7
    elif i == 9:
        factorial = 1 * 3 * 5 * 7 * 9
    elif i == 11:
        factorial = 1 * 3 * 5 * 7 * 9 * 11
    sum += factorial

print(sum)

输出结果为:

> 39916800

这就是 1!+3!+5!+...+11! 的值。