多边形游戏c++代码示例
时间: 2023-09-10 20:14:18 浏览: 42
以下是一个简单的多边形游戏的C代码示例,其中包括绘制多边形和检测多边形是否被点击:
```c
#include <stdio.h>
#include <graphics.h>
#define MAX_POINTS 50
// 定义一个结构体来存储多边形的点
typedef struct {
int x;
int y;
} point_t;
// 绘制多边形
void draw_polygon(point_t points[], int num_points) {
int i;
for (i = 0; i < num_points; i++) {
line(points[i].x, points[i].y, points[(i+1)%num_points].x, points[(i+1)%num_points].y);
}
}
// 检测多边形是否被点击
int is_polygon_clicked(point_t points[], int num_points, int x, int y) {
int i, j;
int c = 0;
for (i = 0, j = num_points-1; i < num_points; j = i++) {
if (((points[i].y > y) != (points[j].y > y)) &&
(x < (points[j].x - points[i].x) * (y - points[i].y) / (points[j].y - points[i].y) + points[i].x)) {
c = !c;
}
}
return c;
}
int main() {
int gd = DETECT, gm;
initgraph(&gd, &gm, "");
point_t points[MAX_POINTS];
int num_points = 0;
int i = 0;
// 从用户输入中获取多边形点的数量和坐标
printf("Enter the number of points in the polygon: ");
scanf("%d", &num_points);
printf("Enter the coordinates of each point:\n");
for (i = 0; i < num_points; i++) {
printf("Point %d: ", i+1);
scanf("%d %d", &points[i].x, &points[i].y);
}
// 绘制多边形
draw_polygon(points, num_points);
// 检测是否被点击
int x, y;
while (!kbhit()) {
if (ismouseclick(WM_LBUTTONDOWN)) {
getmouseclick(WM_LBUTTONDOWN, x, y);
if (is_polygon_clicked(points, num_points, x, y)) {
printf("The polygon was clicked!\n");
} else {
printf("The polygon was not clicked.\n");
}
}
}
closegraph();
return 0;
}
```
注意,以上代码使用了graphics.h库,因此需要在编译时使用-lgraphics参数。例如,对于gcc编译器,可以使用以下命令来编译代码:
```shell
gcc -o polygon_game polygon_game.c -lgraphics
```
请确保你的编译环境中已经安装了graphics.h库。