不对！函数中sin2(3t)应该理解为sin(3t)*sin(3t)

非常抱歉，我理解错误了。在上一个回答中，我误将sin2(3t)解释为sin(3t)的平方，实际上应该是sin(3t)乘以sin(3t)，这是我疏忽了。以下是修改后的代码：

import math
import turtle

# 设置画布大小
canvas_width = 600
canvas_height = 600

# 初始化画布和画笔
turtle.setup(canvas_width + 50, canvas_height + 50)
turtle.penup()
turtle.goto(-canvas_width / 2, 0)
turtle.pendown()
turtle.goto(canvas_width / 2, 0)
turtle.penup()
turtle.goto(0, -canvas_height / 2)
turtle.pendown()
turtle.goto(0, canvas_height / 2)
turtle.penup()

# 设置参数
wh = canvas_width / 2
hh = canvas_height / 2
t = 0
dt = 0.01

# 绘制函数曲线
turtle.pencolor('blue')
turtle.pensize(2)
turtle.speed(0)
turtle.penup()

while t <= 2 * math.pi:

    x = wh * ((1 + math.cos(5 * t) + math.sin(3 * t) * math.sin(3 * t)) * math.sin(t)) / 4
    y = hh * ((1 + math.cos(2 * t) + math.sin(3 * t) * math.sin(3 * t)) * math.cos(t)) / 4

    turtle.goto(x, y)
    turtle.pendown()

    t += dt

turtle.done()

现在，这段代码应该能够正确地绘制出给定函数的曲线了。