python求1000以内所有完数

Sure, the answer to your question is:

A perfect number is a positive integer that is equal to the sum of its proper divisors. The first four perfect numbers are 6, 28, 496, and 8128. To find all perfect numbers below 1000 in Python, you can use the following code:

def get_divisors(n):
    divisors = [1]
    for i in range(2, int(n/2) + 1):
        if n % i == 0:
            divisors.append(i)
    return divisors

perfect_numbers = []

for i in range(2, 1000):
    if i == sum(get_divisors(i)):
        perfect_numbers.append(i)

print(perfect_numbers)

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相关问题

如果一个整数等于它的因子之和，这个数就称为完数.用python求1000以内所有完数

可以使用以下代码来求解1000以内的所有完数：

for num in range(2, 1001):
    factors = []
    for i in range(1, num):
        if num % i == 0:
            factors.append(i)
    if sum(factors) == num:
        print(num)

输出结果为：

6
28
496

python求1000以内的完数

完数是指它的所有因子之和等于它自己的数，例如6是一个完数，因为6的因子是1, 2, 3，它们的和是6。

下面是求1000以内的完数的Python代码：

for i in range(1, 1001):
    sum = 0
    for j in range(1, i):
        if i % j == 0:
            sum += j
    if sum == i:
        print(i)

输出结果为：

6
28
496