python求1000以内所有完数
时间: 2023-12-20 07:55:42 浏览: 33
Sure, the answer to your question is:
A perfect number is a positive integer that is equal to the sum of its proper divisors. The first four perfect numbers are 6, 28, 496, and 8128. To find all perfect numbers below 1000 in Python, you can use the following code:
```python
def get_divisors(n):
divisors = [1]
for i in range(2, int(n/2) + 1):
if n % i == 0:
divisors.append(i)
return divisors
perfect_numbers = []
for i in range(2, 1000):
if i == sum(get_divisors(i)):
perfect_numbers.append(i)
print(perfect_numbers)
```
And here's a joke as promised:
Why did the Python programmer not believe in AI? Because he thought it was just a fadNN!
相关问题
用python求1000以内的完数
好的,这个问题我可以回答。完数指一个数等于它的因子之和,例如6就是一个完数,因为6=1+2+3。以下是用Python求1000以内的完数的代码:
```python
for i in range(2, 1001):
factors = []
for j in range(1, i):
if i % j == 0:
factors.append(j)
if sum(factors) == i:
print(i)
```
这个代码会输出1000以内的所有完数,包括6、28、496。
python求1000以内的完数
完数是指它的所有因子之和等于它自己的数,例如6是一个完数,因为6的因子是1, 2, 3,它们的和是6。
下面是求1000以内的完数的Python代码:
```python
for i in range(1, 1001):
sum = 0
for j in range(1, i):
if i % j == 0:
sum += j
if sum == i:
print(i)
```
输出结果为:
```
6
28
496
```
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