求Sn=1!+2!+3!+4!+5!+…+n!之值
时间: 2023-12-01 18:42:32 浏览: 31
以下是两种求Sn=1!+2!+3!+4!+5!+…+n!之值的方法:
1.使用for循环计算阶乘和
```python
n = int(input("请输入n的值:"))
sum = 0
factorial = 1
for i in range(1, n+1):
factorial *= i
sum += factorial
print("Sn的值为:", sum)
```
2.使用递归函数计算阶乘和
```python
def factorial(n):
if n == 1:
return 1
else:
return n * factorial(n-1)
n = int(input("请输入n的值:"))
sum = 0
for i in range(1, n+1):
sum += factorial(i)
print("Sn的值为:", sum)
```
相关问题
:求Sn=1!+2!+3!+4!+5!+…+n!之值,
以下是两种方法来求Sn=1!+2!+3!+4!+5!+…+n!之值:
1. Python代码:
```python
n = int(input("请输入n的值:"))
total = 0
for i in range(1, n+1):
factorial = 1
for j in range(1, i+1):
factorial *= j
total += factorial
print("Sn的值为:", total)
```
2. C语言代码:
```c
#include <stdio.h>
int main() {
long long n, i, j, factorial, total = 0;
printf("请输入n的值:");
scanf("%lld", &n);
for (i = 1; i <= n; ++i) {
factorial = 1;
for (j = 1; j <= i; ++j) {
factorial *= j;
}
total += factorial;
}
printf("Sn的值为:%lld", total);
return 0;
}
```
求Sn=1!+2!+3!+4!+5!+…+n!之值C语言
这段C语言代码可以求出Sn=1!+2!+3!+4!+5!+…+n!之值。具体实现方法是通过两个for循环,第一个for循环用来遍历1到n,第二个for循环用来计算每个数的阶乘,并将每个数的阶乘加起来得到总和。最后输出总和即可。
代码如下:
```
#include <stdio.h>
int main() {
long long a=0;
scanf("%lld",&a);
int i=1;
long long total=0;
for(i=1;i<=a;++i){
int b=0;
long long sum=1;
for(b=i;b>0;b=b-1){
sum=sum*b;
}
total=total+sum;
}
printf("%lld",total);
return 0;
}
```