100个人，搬100块砖,女人搬2，男人搬3，两个小孩搬一块砖，问需要多少男人、女人和小孩用c语言编程解决

这是一个简单的编程问题，我们可以使用变量和循环结构来解决它。假设我们用`men`表示男人的数量，`women`表示女人的数量，`children`表示小孩的数量。由于总人数是固定的，所以有：

int total_people = 100;
int total_bricks = 100;

int men_brick_rate = 3;
int women_brick_rate = 2;
int children_brick_rate = 0.5; // 两个小孩搬一块砖

int remaining_bricks = total_bricks;

while (remaining_bricks > 0) {
    if (men_brick_rate <= remaining_bricks && women_brick_rate <= remaining_bricks) {
        men += men_brick_rate;
        women += women_brick_rate;
        remaining_bricks -= men_brick_rate + women_brick_rate;
    } else if (men_brick_rate <= remaining_bricks) { // 如果只剩下男人能搬
        men += remaining_bricks;
        remaining_bricks = 0;
    } else if (women_brick_rate <= remaining_bricks) { // 同理，如果只剩下女人
        women += remaining_bricks;
        remaining_bricks = 0;
    } else { // 其他情况都不成立，意味着只能靠小孩搬完剩余
        children += remaining_bricks / children_brick_rate;
        remaining_bricks %= children_brick_rate; // 因为不可能有分数的小孩
    }
}

// 检查是否有剩余的人数
if (remaining_bricks == 0) {
    printf("需要%d个男人，%d个女人和%d个小孩。\n", men, women, children);
} else {
    printf("无法完全搬完砖，因为剩下的砖超过了小孩的能力。\n");
}