背包问题python代码
时间: 2023-10-28 18:00:17 浏览: 97
当然,下面是一个使用动态规划解决背包问题的Python代码示例:
```python
def knapsack(weights, values, capacity):
n = len(weights)
dp = [[0] * (capacity + 1) for _ in range(n + 1)]
for i in range(1, n + 1):
for j in range(1, capacity + 1):
if weights[i - 1] > j:
dp[i][j] = dp[i - 1][j]
else:
dp[i][j] = max(dp[i - 1][j], values[i - 1] + dp[i - 1][j - weights[i - 1]])
selected_items = []
i, j = n, capacity
while i > 0 and j > 0:
if dp[i][j] != dp[i - 1][j]:
selected_items.append(i - 1)
j -= weights[i - 1]
i -= 1
return dp[n][capacity], selected_items[::-1]
# 示例用法
weights = [2, 3, 4, 5]
values = [3, 4, 5, 6]
capacity = 8
max_value, selected_items = knapsack(weights, values, capacity)
print("最大价值:", max_value)
print("选择的物品:", selected_items)
```
这段代码使用了动态规划思想来解决背包问题。其中,`weights`是物品的重量列表,`values`是物品的价值列表,`capacity`是背包容量。函数`knapsack`返回最大的总价值和被选中的物品列表。
希望这个代码能帮到你!如果你还有其他问题,请随时问我。
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