输出遍历树,在屏幕上输出a+b*(c-d)-e/f的代码
时间: 2023-06-11 07:05:41 浏览: 46
下面是遍历该表达式树并输出代码的示例代码:
```
#include <iostream>
#include <stack>
#include <string>
using namespace std;
struct TreeNode {
char val;
TreeNode* left;
TreeNode* right;
TreeNode(char c) : val(c), left(nullptr), right(nullptr) {}
};
void postOrder(TreeNode* node) {
if (node == nullptr) return;
postOrder(node->left);
postOrder(node->right);
cout << node->val;
}
void traverseAndPrint(const string& expression) {
stack<TreeNode*> s;
for (char c : expression) {
if (isdigit(c)) {
s.push(new TreeNode(c));
}
else {
TreeNode* node = new TreeNode(c);
node->right = s.top(); s.pop();
node->left = s.top(); s.pop();
s.push(node);
}
}
postOrder(s.top());
}
int main() {
string expression = "ab*(c-d)-e/f";
traverseAndPrint(expression);
return 0;
}
```
该代码的思想是将中缀表达式转换为表达式树,然后使用后序遍历输出对应的代码。