用matlab写代码maxz=1.15x4A+1.40 x2c +1.25 x3B +1.06 x5D (xiA,XiB,Xic,XiD ≥ 0( i = 1, 2, 3, 4, 5) X3B ≤ 40000 X2c ≤ 30000 s,ti -1.15x3A-1.06 x4D + X5D=0 -1.15x2a-1.06 xD +X4A + X4D=0 -1.15x1A-1.06 x2D+X3A+X3B+X3D=0 -1.06x1D+X2A+X2c+X2D=0(X1A+X1D=100000

x = optimvar('x',5,'LowerBound',0);
maxz = 1.15*x(1) + 1.40*x(2) + 1.25*x(3) + 1.06*x(5);
s = optimproblem('Objective',maxz);
s.constraints.c1 = x(3) <= 40000;
s.constraints.c2 = x(2) <= 30000;
s.constraints.c3 = -1.15*x(3) - 1.06*x(4) + x(5) == 0;
s.constraints.c4 = -1.15*x(2) - 1.06*x(4) + x(1) == 0;
s.constraints.c5 = -1.15*x(1) - 1.06*x(2) + x(3) + x(4) == 0;
s.constraints.c6 = -1.06*x(5) + x(1) + x(2) == 100000;
[xsol,fval,exitflag,output] = solve(s);
disp(xsol.x); % display the solution of x
disp(fval); % display the optimal objective value

相关问题

用lingo写代码maxz=1.15x4A+1.40 x2c +1.25 x3B +1.06 x5D (xiA,XiB,Xic,XiD ≥ 0( i = 1, 2, 3, 4, 5) X3B ≤ 40000 X2c ≤ 30000 s,ti -1.15x3A-1.06 x4D + X5D=0 -1.15x2a-1.06 xD +X4A + X4D=0 -1.15x1A-1.06 x2D+X3A+X3B+X3D=0 -1.06x1D+X2A+X2c+X2D=0(X1A+X1D=100000

)

maxz = 1.15*x4A + 1.40*x2c + 1.25*x3B + 1.06*x5D

subject to:

x1A + x1D = 100000

-1.15*x1A - 1.06*x2D + x3A + x3B + x3D = 0

-1.15*x2A - 1.06*x4D + x4A + x4D = 0

-1.15*x3A - 1.06*x4D + x5D + x3B + x3D = 0

-1.06*x1D + x2A + x2c + x2D = 0

x3B <= 40000

x2c <= 30000

x1A, x1D, x2A, x2c, x2D, x3A, x3B, x3D, x4A, x4D, x5D >= 0

用lingo编maxz= 1.15x4A+1.40x2c+1.25x3в +1.06x5d 满足约束条件 X1A+X1D =100000 -1.06x1D+X2A+X2C+X2D =0 -1.15x1A-1.06 X2D +X3A +X3b +X3D =0 - 1.15x2A -1.06 X3D +X4A +X4D =0 -1.15x3A-1.06 x4D +X5D =0 X2c ≤30000 ≤40000 X3B xiA，XiB， xic， XiD ≥0 (i=1,2,3,4,5)

以下是满足约束条件的lingo代码：

MIN = 1.15x1A + 1.4x2C + 1.25x3B + 1.06x4D + 1.06x5D

Subject to:
    X1A * X1D = 100000 - 1.06x1D
    X2A * X2C * X2D = 0 - 1.15x1A - 1.06X2D
    X3A * X3B * X3D = 0 - 1.15x2A - 1.06X3D
    X4A * X4D = 0 - 1.15x3A - 1.06x4D
    X5D = 0
    X2C <= 30000
    X2C <= 40000
    X1A, X1D, X2A, X2C, X2D, X3A, X3B, X3D, X4A, X4D, X5D >= 0

注：以上的代码依赖于当前给出的内容，在不同的上下文中，可能需要重新评估。