帮我用c语言写一个简单的俄罗斯方块代码

好的，我可以给您介绍一下俄罗斯方块游戏的实现方法，以及如何用 C 语言写一个简单的俄罗斯方块代码。

俄罗斯方块游戏通常由以下几个部分组成：

1. 方块的定义：定义不同形状的方块，以及它们的旋转状态。

2. 游戏区域：定义游戏区域的大小和边框，以及方块在游戏区域内的移动和堆积。

3. 游戏逻辑：处理玩家的输入和游戏逻辑，包括方块的自动下落、旋转和消除。

下面是一个简单的 C 语言俄罗斯方块代码实现示例，其中主要使用了结构体、二维数组、指针等知识点。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <conio.h>

#define ROW 20
#define COL 10

typedef struct {
    int x, y;
} Point;

typedef struct {
    int shape;
    Point pos;
} Block;

int board[ROW][COL] = {0};

Block blocks = {
    {{{0,0,0,0},
      {0,1,1,0},
      {0,1,1,0},
      {0,0,0,0}}, {3, 0}},
    {{{0,0,0,0},
      {2,2,2,2},
      {0,0,0,0},
      {0,0,0,0}}, {3, 0}},
    //...
};

void init() {
    srand(time(NULL));
}

void draw_block(Block *block) {
    int i, j;
    for (i = 0; i < 4; i++) {
        for (j = 0; j < 4; j++) {
            if (block->shape[i][j]) {
                printf("*");
            } else {
                printf(" ");
            }
        }
        printf("\n");
    }
}

int check_collision(Block *block) {
    int i, j;
    for (i = 0; i < 4; i++) {
        for (j = 0; j < 4; j++) {
            if (block->shape[i][j] && 
                (block->pos.y + i >= ROW || block->pos.x + j < 0 || block->pos.x + j >= COL || board[block->pos.y + i][block->pos.x + j])) {
                return 1;
            }
        }
    }
    return 0;
}

void place_block(Block *block) {
    int i, j;
    for (i = 0; i < 4; i++) {
        for (j = 0; j < 4; j++) {
            if (block->shape[i][j]) {
                board[block->pos.y + i][block->pos.x + j] = block->shape[i][j];
            }
        }
    }
}

void clear_lines() {
    int i, j;
    for (i = ROW - 1; i >= 0; i--) {
        int full = 1;
        for (j = 0; j < COL; j++) {
            if (!board[i][j]) {
                full = 0;
                break;
            }
        }
        if (full) {
            int k;
            for (k = i - 1; k >= 0; k--) {
                for (j = 0; j < COL; j++) {
                    board[k + 1][j] = board[k][j];
                }
            }
            for (j = 0; j < COL; j++) {
                board[j] = 0;
            }
            i++;
        }
    }
}

int main() {
    init();
    Block *current_block = &blocks[rand() % 7];
    Block *next_block = &blocks[rand() % 7];
    while (1) {
        system("cls");
        printf("Next block:\n");
        draw_block(next_block);
        printf("\n\n");

        current_block->pos.x = COL / 2 - 2;
        current_block->pos.y = 0;
        if (check_collision(current_block)) {
            printf("Game over!\n");
            break;
        }

        while (!check_collision(current_block)) {
            current_block->pos.y++;
        }
        current_block->pos.y--;

        while (1) {
            place_block(current_block);
            clear_lines();
            current_block = next_block;
            next_block = &blocks[rand() % 7];

            if (check_collision(current_block)) {
                break;
            }

            int key = getch();
            if (key == 'a') {
                current_block->pos.x--;
                if (check_collision(current_block)) {
                    current_block->pos.x++;
                }
            } else if (key == 'd') {
                current_block->pos.x++;
                if (check_collision(current_block)) {
                    current_block->pos.x--;
                }
            } else if (key == 'w') {
                Block tmp = *current_block;
                int i, j;
                for (i = 0; i < 4; i++) {
                    for (j = 0; j < 4; j++) {
                        tmp.shape[j][3-i] = current_block->shape[i][j];
                    }
                }
                if (!check_collision(&tmp)) {
                    *current_block = tmp;
                }
            } else if (key == 's') {
                current_block->pos.y++;
                if (check_collision(current_block)) {
                    current_block->pos.y--;
                    break;
                }
            }

            system("cls");
            printf("Next block:\n");
            draw_block(next_block);
            printf("\n\n");

            int i, j;
            for (i = 0; i < ROW; i++) {
                for (j = 0; j < COL; j++) {
                    if (board[i][j]) {
                        printf("*");
                    } else {
                        printf(" ");
                    }
                }
                printf("\n");
            }
        }
    }

    return 0;
}

以上代码仅为示例，实际情况可能会更加复杂。如果您想深入学习 C 语言和游戏编程，可以继续学习相关知识。