bresenham圆算法python代码
时间: 2023-10-03 07:08:34 浏览: 190
基于Python实现的Bresenham算法(未优化)
以下是Bresenham圆算法的Python代码:
```python
import pygame
# 初始化Pygame
pygame.init()
# 设置屏幕宽度和高度
SCREEN_WIDTH = 640
SCREEN_HEIGHT = 480
# 创建屏幕对象
screen = pygame.display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT))
# 设置窗口标题
pygame.display.set_caption("Bresenham Circle Algorithm")
# 定义画圆函数
def draw_circle(xc, yc, x, y):
# 绘制圆的8个对称点
screen.set_at((xc + x, yc + y), pygame.Color("white"))
screen.set_at((xc - x, yc + y), pygame.Color("white"))
screen.set_at((xc + x, yc - y), pygame.Color("white"))
screen.set_at((xc - x, yc - y), pygame.Color("white"))
screen.set_at((xc + y, yc + x), pygame.Color("white"))
screen.set_at((xc - y, yc + x), pygame.Color("white"))
screen.set_at((xc + y, yc - x), pygame.Color("white"))
screen.set_at((xc - y, yc - x), pygame.Color("white"))
# 定义Bresenham圆算法函数
def bresenham_circle(xc, yc, r):
x = 0
y = r
d = 3 - 2 * r
while x <= y:
draw_circle(xc, yc, x, y)
x += 1
if d < 0:
d = d + 4 * x + 6
else:
y -= 1
d = d + 4 * (x - y) + 10
# 如果圆心在屏幕中心,则只绘制4个对称点,避免画出重复的点
if xc == SCREEN_WIDTH / 2 and yc == SCREEN_HEIGHT / 2:
if x == y:
screen.set_at((xc + x, yc + y), pygame.Color("white"))
screen.set_at((xc - x, yc + y), pygame.Color("white"))
screen.set_at((xc + x, yc - y), pygame.Color("white"))
screen.set_at((xc - x, yc - y), pygame.Color("white"))
else:
draw_circle(xc, yc, y, x)
# 主循环
def main():
# 设置圆心坐标和半径
xc = SCREEN_WIDTH / 2
yc = SCREEN_HEIGHT / 2
r = 100
# 调用Bresenham圆算法函数
bresenham_circle(xc, yc, r)
# 刷新屏幕
pygame.display.flip()
# 等待退出
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
return
# 调用主函数
if __name__ == '__main__':
main()
```
在这个实现中,我们使用了Pygame库来创建屏幕和绘制圆。Bresenham圆算法被实现为一个单独的函数,它接受圆心坐标和半径作为参数,并在屏幕上绘制圆。主函数将调用Bresenham圆算法函数并等待退出事件。
阅读全文