求方程式ax2 bx c=0的根python

以下是求方程ax2 + bx + c=0的根的Python代码：

import math

a = 2
b = 3
c = 1

delta = b**2 - 4*a*c

if delta < 0:
print("方程无实数根")
elif delta == 0:
x = -b/(2*a)
print("方程有一个实数根：x =", x)
else:
x1 = (-b + math.sqrt(delta))/(2*a)
x2 = (-b - math.sqrt(delta))/(2*a)
print("方程有两个实数根：x1 =", x1, "x2 =", x2)