最小费用流matlab
时间: 2023-10-16 08:24:05 浏览: 101
以下是一个 MATLAB 最小费用流的示例代码:
```
function [flow, cost] = minCostFlow(Cap, Cost, Source, Sink)
% Cap: 容量矩阵
% Cost: 费用矩阵
% Source: 源点
% Sink: 汇点
% flow: 最大流
% cost: 最小费用
n = size(Cap, 1);
flow = 0;
cost = 0;
while true
% 使用 Dijkstra 算法寻找增广路径
[dist, prev] = dijkstra(Cap, Cost, Source, Sink);
if dist(Sink) == inf
break;
end
% 计算增广路径上的最大流量
min_flow = inf;
v = Sink;
while v ~= Source
u = prev(v);
min_flow = min(min_flow, Cap(u, v));
v = u;
end
% 更新残量网络和流
v = Sink;
while v ~= Source
u = prev(v);
Cap(u, v) = Cap(u, v) - min_flow;
Cap(v, u) = Cap(v, u) + min_flow;
cost = cost + Cost(u, v) * min_flow;
v = u;
end
flow = flow + min_flow;
end
end
function [dist, prev] = dijkstra(Cap, Cost, Source, Sink)
n = size(Cap, 1);
dist = inf(1, n);
prev = zeros(1, n);
visited = false(1, n);
dist(Source) = 0;
while true
% 找到未访问的距离最小的点
min_dist = inf;
u = -1;
for i = 1:n
if ~visited(i) && dist(i) < min_dist
min_dist = dist(i);
u = i;
end
end
if u == -1
break;
end
visited(u) = true;
% 更新所有与 u 相邻的点的距离
for v = 1:n
if Cap(u, v) > 0 && dist(u) + Cost(u, v) < dist(v)
dist(v) = dist(u) + Cost(u, v);
prev(v) = u;
end
end
end
end
```
使用示例:
```
Cap = [0 3 2 0; 0 0 0 2; 0 0 0 2; 0 0 0 0];
Cost = [0 1 2 0; 0 0 0 1; 0 0 0 5; 0 0 0 0];
[flow, cost] = minCostFlow(Cap, Cost, 1, 4);
```
在这个示例中,我们有一个 4 个节点的有向图,其中节点从 1 到 4 标号。Cap 矩阵表示每个边的容量,Cost 矩阵表示每个边的费用。我们尝试寻找从节点 1 到节点 4 的最小费用流,最终得到的最小费用为 6,最大流为 4。
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