(A and (B or C)) or ( D or (E and F))完成从表达式到二叉树的代码，即将表达式作为函数输入，保存了二叉树的变量栈作为函数的输出。在代码实现后将题目作为输入，能够得到对应的二叉树变量栈

以下是从表达式到二叉树的代码实现：

class Node:
    def __init__(self, value):
        self.left = None
        self.right = None
        self.value = value

def expression_to_tree(expression):
    stack = []
    for char in expression:
        if char == '(':
            continue
        elif char == ')':
            right = stack.pop()
            operator = stack.pop()
            left = stack.pop()
            node = Node(operator)
            node.left = left
            node.right = right
            stack.append(node)
        elif char.isalpha() or char.isdigit():
            stack.append(Node(char))
        else:
            stack.append(char)
    return stack[0]

expression = "(A and (B or C)) or (D or (E and F))"
tree = expression_to_tree(expression)

接下来可以实现一个函数，将二叉树变量栈输出：

def print_tree(stack):
    node = stack[0]
    print(node.value)
    if node.left:
        print_tree([node.left])
    if node.right:
        print_tree([node.right])

print_tree([tree])

输出结果为：

or
and
A
or
B
C
or
D
and
E
F