用循环链表解决约瑟夫问题，并实现一个复杂的主程序python

好的，我理解了你的问题。以下是用循环链表解决约瑟夫问题的Python代码：

class Node:
    def __init__(self, data):
        self.data = data
        self.next = None

class CircularLinkedList:
    def __init__(self):
        self.head = None

    def add_node(self, data):
        new_node = Node(data)
        if self.head is None:
            self.head = new_node
            self.head.next = self.head
        else:
            current = self.head
            while current.next != self.head:
                current = current.next
            current.next = new_node
            new_node.next = self.head

    def remove_node(self, node):
        if self.head == node:
            current = self.head
            while current.next != self.head:
                current = current.next
            current.next = self.head.next
            self.head = self.head.next
        else:
            current = self.head
            while current.next != self.head:
                if current.next == node:
                    current.next = node.next
                    break
                current = current.next

def josephus(n, k):
    linked_list = CircularLinkedList()
    for i in range(1, n+1):
        linked_list.add_node(i)

    current = linked_list.head
    while current.next != current:
        count = 1
        while count != k:
            current = current.next
            count += 1
        linked_list.remove_node(current)
        current = current.next

    return current.data

if __name__ == '__main__':
    n = 10
    k = 3
    survivor = josephus(n, k)
    print(f"The survivor is {survivor}.")

在主程序中，我设置了$n=10$和$k=3$。你也可以根据需要更改这些值。运行程序后，输出将显示最后一个幸存者的编号。