已知稀疏矩阵A和B，编写代码实现基于三元组顺序表实现A+B的运算

好的，根据您的要求，我会给出代码实现基于三元组顺序表的稀疏矩阵A+B的运算。以下是代码：

class Triple(object):
    def __init__(self, row, col, data):
        self.row = row
        self.col = col
        self.data = data
 
 
class SparseMatrix(object):
    def __init__(self, row_num, col_num):
        self.row_num = row_num
        self.col_num = col_num
        self.triples = []
 
    def append(self, row, col, data):
        if row >= 0 and row < self.row_num and col >= 0 and col < self.col_num and data != 0:
            self.triples.append(Triple(row, col, data))
 
    def __add__(self, other):
        if self.row_num != other.row_num or self.col_num != other.col_num:
            return None
 
        result = SparseMatrix(self.row_num, self.col_num)
        i, j = 0, 0
        while i < len(self.triples) and j < len(other.triples):
            a, b = self.triples[i], other.triples[j]
            if a.row < b.row or (a.row == b.row and a.col < b.col):
                result.append(a.row, a.col, a.data)
                i += 1
            elif a.row > b.row or (a.row == b.row and a.col > b.col):
                result.append(b.row, b.col, b.data)
                j += 1
            else:
                result.append(a.row, a.col, a.data + b.data)
                i += 1
                j += 1
 
        while i < len(self.triples):
            a = self.triples[i]
            result.append(a.row, a.col, a.data)
            i += 1
 
        while j < len(other.triples):
            b = other.triples[j]
            result.append(b.row, b.col, b.data)
            j += 1
 
        return result

使用方法：

首先，我们要创建两个稀疏矩阵A和B，然后调用`__add__`方法进行相加运算，最后输出结果即可。

# 创建稀疏矩阵A和B
A = SparseMatrix(3, 3)
A.append(0, 0, 1)
A.append(0, 2, 3)
A.append(1, 1, 5)
A.append(2, 0, 2)
A.append(2, 2, 4)
 
B = SparseMatrix(3, 3)
B.append(0, 1, 2)
B.append(1, 0, 4)
B.append(1, 1, 6)
B.append(2, 2, 1)
 
# 计算A + B
C = A + B
 
# 输出结果
for triple in C.triples:
    print(triple.row, triple.col, triple.data)

输出结果为：

0 0 1
0 1 2
0 2 3
1 0 4
1 1 11
2 0 2
2 2 5

希望我的回答能够帮到您，如果还有问题，请随时提出。