使用循环计算 s=1/1!−1/2!+1/3!−1/4!+…+1/99!−1/100! 的值 c语言

以下是使用循环计算 s=1/1!−1/2!+1/3!−1/4!+…+1/99!−1/100! 的值的C语言代码：

#include <stdio.h>

int main() {
    int n = 100;
    double sum = 0, factorial = 1;
    for (int i = 1; i <= n; i++) {
        factorial *= i;
        if (i % 2 == 0) {
            sum -= 1 / factorial;
        } else {
            sum += 1 / factorial;
        }
    }
    printf("Sum = %lf", sum);
    return 0;
}