编写一个c＋＋程序，计算s=1+1/2+1/4+1/7+1/11+1/16…当第i项小于十的负四次方时结束

#include <iostream>
using namespace std;

int main() {
double s = 1;
double i = 2;
double num = 2;

while(1) {
num = num + i;
double temp = 1.0 / num;
if(temp < 1e-4) {
break;
}
s += temp;
i++;
}

cout << "s = " << s << endl;

return 0;
}