能不能帮我写一个用python生成贪吃蛇的代码
时间: 2023-05-22 20:00:50 浏览: 72
100行python代码完成的贪吃蛇游戏,简单方便快捷,下载即可运行,可做毕业设计
当然可以,以下是一个简单的Python代码示例:
```python
import pygame
import random
# 初始化 Pygame
pygame.init()
# 设置游戏窗口大小
window_width = 400
window_height = 400
window = pygame.display.set_mode((window_width, window_height))
# 设置游戏标题
pygame.display.set_caption('贪吃蛇')
# 定义颜色
white = (255, 255, 255)
black = (0, 0, 0)
red = (255, 0, 0)
green = (0, 255, 0)
# 定义蛇的初始位置和大小
snake_block_size = 10
snake_speed = 15
x1 = window_width / 2
y1 = window_height / 2
x1_change = 0
y1_change = 0
snake_List = []
Length_of_snake = 1
# 定义食物的初始位置
foodx = round(random.randrange(0, window_width - snake_block_size) / 10.0) * 10.0
foody = round(random.randrange(0, window_height - snake_block_size) / 10.0) * 10.0
# 定义字体
font_style = pygame.font.SysFont(None, 30)
# 定义得分函数
def Your_score(score):
value = font_style.render("Your Score: " + str(score), True, white)
window.blit(value, [0, 0])
# 定义蛇的函数
def our_snake(snake_block_size, snake_List):
for x in snake_List:
pygame.draw.rect(window, green, [x[0], x[1], snake_block_size, snake_block_size])
# 游戏循环
game_over = False
while not game_over:
for event in pygame.event.get():
if event.type == pygame.QUIT:
game_over = True
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
x1_change = -snake_block_size
y1_change = 0
elif event.key == pygame.K_RIGHT:
x1_change = snake_block_size
y1_change = 0
elif event.key == pygame.K_UP:
y1_change = -snake_block_size
x1_change = 0
elif event.key == pygame.K_DOWN:
y1_change = snake_block_size
x1_change = 0
# 判断蛇是否碰到边界
if x1 >= window_width or x1 < 0 or y1 >= window_height or y1 < 0:
game_over = True
# 更新蛇的位置
x1 += x1_change
y1 += y1_change
# 绘制游戏窗口
window.fill(black)
pygame.draw.rect(window, red, [foodx, foody, snake_block_size, snake_block_size])
snake_Head = []
snake_Head.append(x1)
snake_Head.append(y1)
snake_List.append(snake_Head)
if len(snake_List) > Length_of_snake:
del snake_List[0]
for x in snake_List[:-1]:
if x == snake_Head:
game_over = True
our_snake(snake_block_size, snake_List)
Your_score(Length_of_snake - 1)
pygame.display.update()
# 判断蛇是否吃到食物
if x1 == foodx and y1 == foody:
foodx = round(random.randrange(0, window_width - snake_block_size) / 10.0) * 10.0
foody = round(random.randrange(0, window_height - snake_block_size) / 10.0) * 10.0
Length_of_snake += 1
# 控制游戏速度
clock = pygame.time.Clock()
clock.tick(snake_speed)
# 退出 Pygame
pygame.quit()
```
希望这个代码对你有所帮助!
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