C语言从键盘任意输入a，b，c的值，编程计算并输出一元二次方程ax2+bx+c=0的根，当a=0时，输出"It is not a quadratic equation!\n"，当a≠0时，分b2−4ac>0、b2−4ac=0、b2−4ac<0三种情况计算并输出方程的根。 提示：公式为： **输入格式要求："%f,%f,%f" 提示信息："Please enter the coefficients a,b,c:" **输出格式要求："It is not a quadratic equation!\n" "x1 = x2 = %.2f\n" "x1 = %.2f, x2 = %.2f\n" "x1 = %.2f+%.2fi, " "x2 = %.2f-%.2fi\n"

好的，以下是您需要的C语言代码：

#include <stdio.h>
#include <math.h>

int main()
{
    float a, b, c, delta, x1, x2, realPart, imagPart;

    printf("Please enter the coefficients a,b,c:");
    scanf("%f,%f,%f", &a, &b, &c);

    if (a == 0)
    {
        printf("It is not a quadratic equation!\n");
    }
    else
    {
        delta = b * b - 4 * a * c;

        if (delta > 0)
        {
            x1 = (-b + sqrt(delta)) / (2 * a);
            x2 = (-b - sqrt(delta)) / (2 * a);
            printf("x1 = %.2f, x2 = %.2f\n", x1, x2);
        }
        else if (delta == 0)
        {
            x1 = x2 = -b / (2 * a);
            printf("x1 = x2 = %.2f\n", x1);
        }
        else
        {
            realPart = -b / (2 * a);
            imagPart = sqrt(-delta) / (2 * a);
            printf("x1 = %.2f+%.2fi, x2 = %.2f-%.2fi\n", realPart, imagPart, realPart, imagPart);
        }
    }

    return 0;
}

希望能够帮到您！