编写程序，定义矩形类rectangle，需满足如下要求：所有成员函数的定义放在类定义外；定义成员变量x1,y1,x2,y2对应矩形的左上角坐标(x1,y1)和右下角坐标(x2,y2)。定义至少两个构造

这道题目要求编写程序，定义一个矩形类rectangle，并且需要满足以下要求：所有成员函数的定义放在类定义外；定义成员变量x1、y1、x2、y2对应矩形的左上角坐标(x1,y1)和右下角坐标(x2,y2)。至少需要构建两个构造函数来实现矩形的构造。

相关问题

定义一个Point类，派生出Rectangle和Circle类，计算个派生类对象的面积Area()。 要求：①Point类，Rectangle和Circle类都有成员变量、成员函数； ②分别写出他们的构造函数和析构函数； ③在main函数中实现输出。 ④力争做到数据输入输出的直观性。

以下是一个可能的实现，其中Point类包含了x和y坐标，Rectangle类包含了左上角和右下角两个点的坐标，Circle类包含了圆心和半径：

#include <iostream>
#include <cmath>

using namespace std;

class Point {
public:
    Point(double x = 0, double y = 0);
    ~Point();
    double getX() const;
    double getY() const;
    void setX(double x);
    void setY(double y);
private:
    double m_x;
    double m_y;
};

class Rectangle : public Point {
public:
    Rectangle(double x1 = 0, double y1 = 0, double x2 = 0, double y2 = 0);
    ~Rectangle();
    double getWidth() const;
    double getHeight() const;
    double getArea() const;
private:
    double m_width;
    double m_height;
};

class Circle : public Point {
public:
    Circle(double x = 0, double y = 0, double r = 0);
    ~Circle();
    double getRadius() const;
    double getArea() const;
private:
    double m_radius;
};

Point::Point(double x, double y) : m_x(x), m_y(y) {
    cout << "Constructing Point (" << m_x << ", " << m_y << ")" << endl;
}

Point::~Point() {
    cout << "Destructing Point (" << m_x << ", " << m_y << ")" << endl;
}

double Point::getX() const {
    return m_x;
}

double Point::getY() const {
    return m_y;
}

void Point::setX(double x) {
    m_x = x;
}

void Point::setY(double y) {
    m_y = y;
}

Rectangle::Rectangle(double x1, double y1, double x2, double y2) :
        Point(x1, y1), m_width(fabs(x2 - x1)), m_height(fabs(y2 - y1)) {
    cout << "Constructing Rectangle (" << getX() << ", " << getY() << "), width = " << m_width << ", height = " << m_height << endl;
}

Rectangle::~Rectangle() {
    cout << "Destructing Rectangle (" << getX() << ", " << getY() << "), width = " << m_width << ", height = " << m_height << endl;
}

double Rectangle::getWidth() const {
    return m_width;
}

double Rectangle::getHeight() const {
    return m_height;
}

double Rectangle::getArea() const {
    return m_width * m_height;
}

Circle::Circle(double x, double y, double r) : Point(x, y), m_radius(r) {
    cout << "Constructing Circle (" << getX() << ", " << getY() << "), radius = " << m_radius << endl;
}

Circle::~Circle() {
    cout << "Destructing Circle (" << getX() << ", " << getY() << "), radius = " << m_radius << endl;
}

double Circle::getRadius() const {
    return m_radius;
}

double Circle::getArea() const {
    return M_PI * m_radius * m_radius;
}

int main() {
    Rectangle r(1, 1, 4, 3);
    Circle c(2, 2, 2);
    cout << "Rectangle area: " << r.getArea() << endl;
    cout << "Circle area: " << c.getArea() << endl;
    return 0;
}

在main函数中，我们创建了一个Rectangle对象和一个Circle对象，并且分别调用它们的getArea()函数计算面积并输出。程序输出如下：

Constructing Point (1, 1)
Constructing Rectangle (1, 1), width = 3, height = 2
Constructing Point (2, 2)
Constructing Circle (2, 2), radius = 2
Rectangle area: 6
Circle area: 12.5664
Destructing Circle (2, 2), radius = 2
Destructing Point (2, 2)
Destructing Rectangle (1, 1), width = 3, height = 2
Destructing Point (1, 1)

在rectangle中定义一个Rectangle类，类中包含x,y两个对象，分别代表矩形左上角和右下角顶点的坐标。包含的成员函数：构造函数和求矩形面积函数

好的，这是一个关于编程的问题，我可以回答。在Rectangle类中，可以定义如下的构造函数和求矩形面积函数：

class Rectangle {
public:
    Rectangle(int x1, int y1, int x2, int y2) {
        topLeft = {x1, y1};
        bottomRight = {x2, y2};
    }
    int area() const {
        int width = bottomRight.x - topLeft.x;
        int height = bottomRight.y - topLeft.y;
        return width * height;
    }
private:
    struct Point {
        int x;
        int y;
    };
    Point topLeft;
    Point bottomRight;
};

其中，构造函数接受四个整数参数，分别代表矩形左上角和右下角顶点的 x、y 坐标。在构造函数中，我们将这些坐标存储到类的内部成员变量中。求矩形面积函数则计算矩形的宽和高，然后返回宽乘以高的结果。