用while编写程序,计算下列公式中s的值 ， s=1+(1+2)+(1+2+3)十…+(1+2+3+…+n)

n = int(input("请输入正整数n："))
s = 1
i = 2
while i <= n:
j = 1
t = 1
while j <= i:
t = t * j
j = j + 1
s = s * t
i = i + 1
print("s的值为：", s)