编程求1+1/2+1/3+1/4+1/5+……和，直到最后一项的值小于10-5为止，输出求和的项数及求和值。

以下是C++语言的代码实现：

#include <iostream>
#include <cmath>
using namespace std;

int main() {
    double sum = 0.0;
    int count = 0;
    double n = 1.0;
    while (n >= pow(10, -5)) {
        sum += n;
        count++;
        n = 1.0 / (count + 1);
    }
    cout << "求和的项数为：" << count << endl;
    cout << "求和的值为：" << sum << endl;
    return 0;
}