帮我用c语言编写用坐标转移法求(pow(3 * x - 2 * y - 5, 4) + pow(x + y, 2) + pow(x + 3 * y - 1, 6))的最小值

以下是使用坐标转移法求解的C语言代码：

#include <stdio.h>
#include <math.h>

double f(double x, double y){
    return pow(3 * x - 2 * y - 5, 4) + pow(x + y, 2) + pow(x + 3 * y - 1, 6);
}

void coordinateDescent(double *x, double *y, double eps, double alpha){
    double prev_x, prev_y, dx, dy;
    do{
        prev_x = *x;
        prev_y = *y;
        dx = alpha * (2 * (*x + (*y)) + 6 * (*x + 3 * (*y) - 1));
        dy = alpha * (8 * (3 * (*x) - 2 * (*y) - 5) - 2 * (*x + (*y)) + 6 * pow(*x + 3 * (*y) - 1, 5));
        *x = *x - dx;
        *y = *y - dy;
    } while(fabs(*x - prev_x) > eps || fabs(*y - prev_y) > eps);
}

int main(){
    double x = 0, y = 0, eps = 0.0001, alpha = 0.01;
    coordinateDescent(&x, &y, eps, alpha);
    printf("The minimum value of the function is %.4f\n", f(x, y));
    printf("The values of x and y at this minimum point are %.4f and %.4f, respectively.\n", x, y);
    return 0;
}

在函数`f`中，我们计算了给定的函数。在函数`coordinateDescent`中，我们使用坐标转移法来更新变量x和y的值。`eps`是我们设置的收敛阈值，`alpha`是步长大小。在主函数中，我们调用`coordinateDescent`函数来计算函数的最小值，并输出结果。