用Python编写百马百担。现有100匹马需驮100担货，其中大马驮3担，中马驮2担，两匹小马驮一担。问一百匹马中大马、中马、小马各多少?

这是一个经典的数学分配问题，可以使用Python的循环和条件判断来解决。我们可以创建三个变量分别表示大马、中马和小马的数量，并通过迭代来找到合适的组合。以下是一个简单的解决方案：

# 初始化变量
total_horses = 100
total_loads = 100
big_horse_load = 3
medium_horse_load = 2
small_horse_load = 1 / 2

# 初始化计数器
count_big_horses = 0
count_medium_horses = 0
count_small_horses = 0

# 循环直到所有货物都被装载
while count_big_horses * big_horse_load + count_medium_horses * medium_horse_load + count_small_horses * small_horse_load < total_loads:
    # 尝试增加一个小马对
    if count_small_horses < total_horses // 2:  # 如果小马数量不足总数的一半，则增加一对
        count_small_horses += 1
    else:  # 否则尝试增加一个中马
        if count_medium_horses < total_horses - count_big_horses - (total_horses // 2):  # 避免中马过多导致小马不够
            count_medium_horses += 1
        else:  # 中马也无法增加，尝试增加一个大马
            count_big_horses += 1

# 计算剩余的马匹类型
remaining_big_horses = total_horses - count_big_horses
remaining_medium_horses = total_horses - count_medium_horses - count_big_horses

print(f"大马：{count_big_horses}, 中马：{count_medium_horses}, 小马：{count_small_horses}")