用python代码，迭代法求解x^3+e^x/2+5x-6=0的解

在Python中，可以使用数值方法如牛顿迭代法（Newton-Raphson method）来近似求解非线性方程`f(x) = x**3 + e**x / 2 + 5 * x - 6 = 0`。这里是一个简单的实现示例：

import math
def f(x):
    return x**3 + math.exp(x / 2) + 5 * x - 6

def newton_raphson_method(starting_guess, tolerance=1e-8, max_iterations=100):
    for _ in range(max_iterations):
        x_new = starting_guess - f(starting_guess) / f_derivative(starting_guess)
        if abs(x_new - starting_guess) < tolerance:
            return x_new
        starting_guess = x_new
    print("Maximum iterations reached without convergence.")
    return None

def f_derivative(x):
    return 3 * x**2 + math.exp(x / 2) + 5

# 设定初始猜测值（例如，我们可以从零开始）
initial_guess = 0
solution = newton_raphson_method(initial_guess)
print(f"Solution found using Newton's method: {solution}")