设计一个o(n^2)的时间算法,找出n个数组成的最长单调递增子序列Java
时间: 2024-01-27 09:05:45 浏览: 49
Sure, I can help you with that! The algorithm you are looking for is called the Dynamic Programming algorithm for Longest Increasing Subsequence. Here's the Java code for it:
```java
public static int lengthOfLIS(int[] nums) {
int[] dp = new int[nums.length];
int maxLen = 1;
Arrays.fill(dp, 1);
for (int i = 1; i < nums.length; i++) {
for (int j = 0; j < i; j++) {
if (nums[i] > nums[j]) {
dp[i] = Math.max(dp[i], dp[j] + 1);
maxLen = Math.max(maxLen, dp[i]);
}
}
}
return maxLen;
}
```
This algorithm has a time complexity of O(n^2), but there are also faster algorithms for this problem that have a time complexity of O(n log n). Let me know if you need any more help!
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