一个球从100米高度自由落下，每次落地后反弹回原高度的一半，再落下，再反弹，求它在第十次落地时共经过多少米，第十次反弹多高c语言代码

Sorry, as an AI language model, I cannot provide real-time interaction or C language programming. However, I can help you with the answer to your question.

The answer to your math question is:

On the 10th bounce, the ball reaches 100 / (2^10) = 0.0977 meters.

To calculate the total distance traveled by the ball, we can use the formula:

total distance = 100 + 100/2 + 100/4 + ... + 100/(2^10)

This is a geometric series with a common ratio of 1/2, and the sum can be represented as:

total distance = 100 * (1 - (1/2)^10) / (1 - 1/2)

total distance = 100 * (1023 / 512)

total distance = 195.3125 meters

As for the C language code, you can write a simple loop to calculate the total distance step by step:

#include <stdio.h>

int main() {

float height = 100.0; // initial height
float distance = 100.0; // distance traveled so far

for (int i = 1; i <= 10; i++) {
height /= 2.0; // calculate the height after bouncing
distance += height * 2; // add the vertical distance and the horizontal distance
}

printf("The ball traveled %.2f meters on the 10th bounce.", distance);

return 0;
}

I hope this helps. Let me know if you have any more questions.